I assume you mean copper(II) oxide, which is black, and not copper(I) oxide which is orangey-red.copper oxide + sulfuric acid --> copper sulfate + water.
Copper oxide+ Sulphuric acid ----> copper sulphate +water
Copper oxide + Sulfuric acid = Copper sulfate + Water
CuO + H2SO4 --> CuSO4 + H2O
The chemical equation is:CuO + H2SO4 = CuSO4 + H2O
Copper + sulfuric acid = Copper sulphate
CuO + H2SO4 --> CuSO4 + H2O
The following is the equation: CuO + H2SO4 --> CuSO4 + H2O The products formed are copper (II) sulfate and water.
zinc oxide + sulfuric acid -> water + zinc sulfate
Copper sulfate and water :)
to get copper sulphate and water
Yes, Copper oxide does fizz when it reacts with Sulphuric Acid
When you add black copper oxide to sulfuric acid, the solution turns blue because copper sulfate was formed and it is a colored compound.
neutralisation
CuO + H2SO4 ---> CuSO4 + H2O - it needs no balancing.
The ionic equation for a reaction between hydrochloric acid and copper oxide is: 2H+ + O2- -> H2O
Copper (II) oxide and sulphuric acid form copper (II) sulphate, CuO + H2SO4 = CuSO4 + H2o
sulphuric oxide ;0
copper nitrade + water :)
magnesium carbonate + sulfuric acid = magnesium oxide= carbon dioxide
This equation is CaO + H2SO4 = CaSO4 + H2O.
What is the colour of the solution formed when copper oxide is dissolved in dilute sulphuric acid? it turns blue!!!!!!!!!!!!!!!!!!!
# Sodium Oxide + Sulfuric Acid > Sodium Sulfate + Water Na2O(S) + H2SO4 (aq) > Na2SO4 (aq) + H2O (l)
4. The chemical equation is Cu + H2SO4 → CuSO4 + H2. Copper and sulfuric acid have the same coefficient (1), so the same number of moles of copper and sulfuric acid are used.
water and copper(II)sulfate CuO + H2SO4 --> CuSO4 + H2O
Ca(OH)2 + H2SO4 ---->