Top Answer

If y equals 5x-15 and x equals 1 then the value of y comes out to be -10.

So y equals 5x-15 is -10.

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0Transitive property: If 8 equals x and x equals y, then 8 equals y.

If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.

x equals -12 and y equals 1/4 of -12, so y = -3.

y is directly proportional to x. When y = 15, x = 3 therefore y = 5x When x = 12, then y = 5 x 12 = 60.

Half correct because x = 2 and y = 6

Y equals 1 and X equals 1

If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2

x+2y-2x-y=x y-x=x y=2x

No. In fact, under normal rules of operation, x-y equals y-x only when x = y.

y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1

The answer depends on what x and y are!

It depends on how y depends on x.

y = 10x where x = 478 y = 10 x 478 = 4780

x=4 y=x+3 y=4+3 y=7

y = x - 15. We know x = 9.4 y = 9.4 - 15 y = -5.6

If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²

x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32

If X+Y=5;X=4, then x=4 and y=1

y/x is a constant; so first of you can solve for this constant. y/x=6/-3, or y/x=-2 y/4=-2 y=-8

If x+y = 3 and y times x = 2 then y = 1.

x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.

x + y + x = 2x + y

y = x/k so k = 1/25; when x = 1, x/k, hence y, = 25

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