It is slope intercept form. The equation for slope intercept form is y=mx+b which is like your equation y=5x+6
y = 5x + 6At the x-intercept, y = 0 .5x + 6 = 05x = -6x = -6/5
5x + y = 6 so that y = 6 - 5x Also x +2y = 1 so that x + 2*(6-5x) = 1 or x + 12 - 10x = 1 => 9x = 11 or x = 11/9 and then y = 6 - 5x = 6 - 55/9 = -1/9
If x=6 and y=8, then [ 5x + 8y ] = 5(6) + 8(8) = 30 + 64 = 94
eqn1 5x - y = -6eqn2 -x + y = 2rearrange eqn1 to isolate yy = -1*(-6-5x)y = 6+5xsubstitute this into eqn2-x + 6 + 5x = 24x + 6 = 24x = -4x = -1substituting this into eqn1-5 -y = -6y = 1
27 + y = 42 - 4y so 5y = 15 making y = 3 and x = 6
How do you add 2x plus 3y equals 18 in 5x-y equals 11
5x+18 = 2x+9 5x-2x = 9-18 3x = -9 x = -3 and y = 3
The ordered pair is (1, 1).
if: 2x + 6 = -6 then: 2x = -12 x = -6 if: 5x + 7y = 1 then: 5(-6) + 7y = 1 7y = 31 y = 31/7
It is: y = -1/5x+7 that is perpendicular to y = 5x+7
-5x + 6y = 24 6y = 5x + 24 y = 5/6 x + 4 the slope is 5 6
Add: 5x - y + x + y + 8 + 10 ie 6x = 18 so x = 3 and y = 7
If: x = 7 Then: y = (2*7)+3 = 17 And: 5x+y = (5*7)+17 = 52
5x+8 = 10x+35x-10x = 3-8-5x = -5x = 1 and by substituting the value of x into the equations y = 13
Point Slope Form - Y=.5X+1.5
3y = 5xy = x + 23y = 5x3(x + 2) = 5x3x + 6 = 5x3x - 3x + 6 = 5x - 3x6 = 2x6/2 = 2x/23 = xy = x + 2 = 3 + 2 = 5Thus, the solution of the set is (3, 5)Check:
2X + 5Y = 6 5Y = - 2X + 6 Y = - 2/5X + 6/5 ----------------------------------and 5X - 2Y = 8 2Y = - 5X + 8 Y = - 5/2 + 4 ------------------- Look like intersecting lines, though not perpendicular
3x-y = 9 2x+y = 6 Add both equations together: 5x = 15 x = 3 and y = 0
The answer is 79. Since you know the values of x and y, you can simply substitute them into the equation to find the answer. x = 6 y = 7 5x + 7y = 5(6) + 7(7) = 30 +49 = 79
y=-5x+8 the slope is -5.
5x - y = 6 or y = 5x - 6 The slope is 5, which means that the line makes an angle such that its tangent is 5 and it intercepts the y-axis at the point (0, -6)
Sounds like a system of equations. Y + 5X = - 2 - 15X - 3Y = 6 substitution using first equation Y + 5X = - 2 Y = - 5X - 2 ==========insert into other equation as this is Y - 15X - 3(- 5X - 2) = 6 - 15X + 15X + 6 = 6 ========================This looks to be a dependent system that has an infinite number of solutions
The slope is ' 5 ', so both lines MUST be parallel.
The question contains two equations:5x - 6y = 15 5x + y = 2 There are no inequalities in the question.