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What mas of CaCL2 should be used to make 4.5 L of .320 M CaCL2 solution?
Wiki User
∙ 13y ago
Molarity = moles of solute/Liters of solution
0.320 M CaCl2 = moles CaCl2/4.5 Liters
= 1.44 moles of CaCl2
1.44 moles CaCl2 (110.978 grams/ 1 mole CaCl2)
= 159.81 grams needed so, considering the sigi figis, 160 grams needed.
Wiki User
∙ 13y ago
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What is the concentration of nitric acid in moles per liter in a sample which has density 1.41gm per ml and the mass percent of nitric acid is 69 percent?
Molarity is probably the most commonly used unit of concentration. It is the number of moles of solute per liter of solution (not necessarily the same as the volume of solvent!). Example: What is the molarity of a solution made when water is added to 11 g CaCl2 to make 100 mL of solution? Solution: 11 g CaCl2 / (110 g CaCl2 / mol CaCl2) = 0.10 mol CaCl2 100 mL x 1 L / 1000 mL = 0.10 L molarity = 0.10 mol / 0.10 L molarity = 1.0 M http://chemistry.about.com/od/lecturenotesl3/a/concentration.htm http://www.tpub.com/content/MIL-SPEC/MIL-P/MIL-P-71158/MIL-P-7115800013.htm http://www.tpub.com/content/armymedical/md0837/md08370139.htm
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What is the concentration of nitric acid in moles per liter in a sample which has density 1.41gm per ml and the mass percent of nitric acid is 69 percent?
Molarity is probably the most commonly used unit of concentration. It is the number of moles of solute per liter of solution (not necessarily the same as the volume of solvent!). Example: What is the molarity of a solution made when water is added to 11 g CaCl2 to make 100 mL of solution? Solution: 11 g CaCl2 / (110 g CaCl2 / mol CaCl2) = 0.10 mol CaCl2 100 mL x 1 L / 1000 mL = 0.10 L molarity = 0.10 mol / 0.10 L molarity = 1.0 M http://chemistry.about.com/od/lecturenotesl3/a/concentration.htm http://www.tpub.com/content/MIL-SPEC/MIL-P/MIL-P-71158/MIL-P-7115800013.htm http://www.tpub.com/content/armymedical/md0837/md08370139.htm
How are percentage mass calculations used?
mass of the solute/(mass of solution + mass of the solute) x 100%ie: if 67.1g of CaCl2 is added to 275g of water, calculate the mass percent of CaCl2 in the solution.67.1/342.1=.1961.1961 x 100% = 19.6% of CaCl2
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