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Taking rust to be Fe2O3, you would have the following reaction:Fe2O3 + 6HCl ==> 2FeCl3 + 3H2O

100 g Fe2O3 x 1 mole Fe2O3/159.7 g = 0.626 moles Fe2O3

moles HCl needed = 0.626 moles Fe2O3 x 6 moles HCl/mole Fe2O3 = 3.76 moles HCl needed

Mass HCl needed = 3.76 moles HCl x 36.5 g/mole = 137 g HCl needed

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Q: What mass of hydrogen chloride is require to react with 100 g of rust?
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