There is no number x such that both x/2 = 1 and x/9 = 1 are true.
I suspect you misunderstood the question, or just worded it extremely badly.
Yes they are equal. Any number divided by itself equals 1
20 can be divided by 20 and by 2. 20 divided by 20 equals 1, and 20 divided by 2 equals 10.
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Just testing the numbers 1 to 9, only 1 through 6 result in an even product. Dividing by 7, 8, or 9 results in an uneven number.76380 divided by 1 equals 7638076380 divided by 2 equals 3819076380 divided by 3 equals 2546076380 divided by 4 equals 1909576380 divided by 5 equals 1527676380 divided by 6 equals 1273076380 divided by 9 equals 8486.67 an uneven number.
No. The divisor may be an integral multiple of the dividend. For example, 3 1/2 divided by 1 3/4 equals 2. (7/2 divided by 7/4)
9/1 18/2 27/3 endless possibilities... The result of any number multiplied by 9, then divided by the number equals 9 :-) Any number can be divided by 9 if its sum of digits can be divided by 9.
2 Yes but 2 divided by half of 2 (1) = 2 which isn't the lowest whole number. I don't think this question has an answer.
2 and 1 third divided by 1 half equals = 42/3
x divided by 1 is x because any number divided by 1 is itself.So the question reduces to solving (?) x = 2.
6 divided by 11 minus 1 divided by 2 equals?