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510.

To be divisible by 3, it must be a multiple of 3.

Thus the required number is a multiple of both 3 and 5, which will be a multiple of their lcm: lcm(3, 5) = 15.

→ 495 ÷ 15 = 33 → first multiple of 15 greater than 495 is 15 x 34 = 510

→ 525 ÷ 15 = 35 → last multiple of 5 less than 525 is 15 x 34 x 510

→ number required is 510.

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Q: What number is a multiple of 5 divisible by 3 but greater than 495 and less than 525?
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