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What ratio did Mendel get when he crossed hid P1 plants to get the f1 generation?

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2013-01-10 23:48:35
2013-01-10 23:48:35

100% heterozygous pea plants. Showing the dominant trait

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3:1 was the ratio of plants expressing contrasting traits that Gregor Mendel calculated in his F2 generation of garden peas.


Mendel used the mathematics in his experiments. He found the ratio of the pea plants who were tall to who were short if every generation and gave the law of inheritance.


For each of the seven characters Medel studied,he found the same 3:1 ratio of plants expressing the contrasting traits in the f2 generation.



Mendels' f2 generation produce a 3:1 ratio of tall plants. By crossing true tall with true short , homologous chromosomes, he wound up with three types of plants, true tall, true short, and tall with a short allele.


A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.


Mendel found a fixed pattern of inheritance in the ratio of 3:1 in the contrasting characters from F1 generation to F2.


Mendel crossed pure breed plants through the process of monohybriting. the offspring came looking alike because they had inherited a dominant gene which makes them tall. When he crossed the offsprings,the inbreds came out with a ratio of 3:1. meaning 3 were tall and one was short. The short one had inherited the recessive gene, which restricted it from growing tall


Mendel first described what is called genetics. He used sweet peas and crossed pure bred plants. For example, he crossed short pure bred (recessive) with tall pure bred plants (dominant). If tall is dominant, all plants would be tall. Crossing these hybrid plants would give a ratio of 3 tall to 1 short. This is the basis from which all studies of genes come from.


There was a 3:1 ratio of tall plants to short plants.


out of total 1064 plants in f2 generation,787 plants were tall & 277 plants were dwarf.Means 3:1 ratio was obtained.




Mendel worked with sweet peas. Not all organisms have such straight forward genetics.


well, that would be Tt and Tt.... so... 1:2:1 is the ratio of the genotype. 3:1 is the ratio of the phenotype. do you go to MHS?


In a monohybrid cross Mendel crossed two true-breeding varieties, one producing round seeds and the other producing wrinkled seeds, all the F1 offspring had round seeds. In the F2 plants, 75% of the seeds were round and 25% were wrinkled. Getting a 3:1 ratio.


Mendel observed phenotypes for seven contrasting characters segregating in to three is to one ratio mathematically and thus he propounded the principle dominance and recessive characters



A snapdragon is an example of an incomplete dominance because when a snapdragon plant having red flowers is crossed with another plant having white flowers, all F1 plants bear red flowers but in F2 generation, the plant population segregates in to 1 red : 2 pink : 1 white flowered plants ratio.


i think he used cross breeding(I think) in the F1 generation, then used the results to self pollinate. dont quote me i am not sure, just what i would think. 9th grade H Bio student



For monohybrid cross the genotype ratio in f2 generation would be 1:2:1 and phenotype ratio would be 3: 1


it is ratio of mono hybrid cross found in f2 generation .this ratio is 3:1


9:3:3:1 was the ratio of Mendel's f2 generation for the two factor cross.




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