CH4, due to the least number of carbon atoms.
It is a molecular formula.This is because the formula C4H10 is not in its lowest ratio, which is C2H5
-1 degrees Celsius or about 30 degrees Fahrenheit.
C4H10(g) is about -126 kJ/mol C4H10(l) is about -147 kJ/mol
Butane (C4H10) Diethyl ether (C4H10O) Butanal (C4H8O) Butanol (C4H10O) Butanoic acid (C4H8O2)
C4h10 + 6.5o2 -> 4co2 + 5h2o
1 mole C4H10 = 58.1222g = 6.022 x 1023 molecules 11.7g C4H10 x 6.022 x 1023 molecules/58.1222g = 1.21 x 1023 molecules C4H10
The melting and boiling points are different. Butane has a melting point of 135.4K and 2-methylpropane [isobutane] has a melting point of 114K. The boiling point of Butane is 272.6K and isobutane @ 261K. It has to do with there structures. J
Butane (C4H10) Melting points: -140 to -134 °C, 133 to 139 K, -220 to -209 °F Boiling points: -1 to 1 °C, 272 to 274 K, 30 to 34 °F
Butane-C4H10 C4H10 - H C4H9 - ? C4H9 + CHO C4H9CHO
(3.5 g C4H10) (1 mol C4H10/58.12 g C4H10) (4 mol C/1 mol C4H10) (6.022 * 1023 C atoms/1 mol C) = 1.45 * 1023
Butane is C4H10. So; 100 grams C4H10 (1mol C4H10/58.12g)(4mol C/1mol C4H10 )(6.022 X 10^23/1mol C) = 4.14 X 10^24 atoms of Carbon.
C4H10 + O2 ------CO2 t H2O?
2C4H10 + 13O2 = 8CO2 + 10H2O
1.02g C4H10 /58.12 g/mol C4H10= .0175 mol C4H10 .0175 mol C4H10 * 10 mol H2O / 2 mol C4H10 = .0877 mol H2O .0877 mol H2O * 18.02 g H2O = 1.58 g H20 Final Answer: 1.58 g H2O
In general: higher number of C atoms, higher boiling point, BUT also the degree of branching (from C4H10), the number of double bonds (C=C) and presence of rings (from cyclo-C3H6) are very important.
Butanes are organic molecules of the formula of C4H10. Butane has a molecular weight of 58.12 grams per mole.
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
It is a hydrocarbon with the formula, C4H10
Butane is a gas.
C4H10 plus 9/2O2 equals 4CO plus 5H2O
Balance this combustion reaction first! 2C4H10 + 13O2 -> 8CO2 + 10H2O 0.86 moles C4H10 (13 moles O2/2 moles C4H10) = 5.6 moles of oxygen required ----------------------------------------
C4H10 has 2 isomers: butane and isobutane (also called 2-methyl propane)
14..4 elements of carbon,10 of hydrogen 2nd Answer: Good grief! There are 2 elements in C4H10: Carbon and Hydrogen.
The reaction is:2 C4H10 + 13 O2 → 8 CO2 + 10 H2OThe answer is 24 moles.
Although I do not know much about this chemical called C2H1010, I do know that carbon has the highest melting point of all the elements and It forms strong bonds, and so naturally some of these characteristics would carry over, and if the bonds are stronger than diatomic Cl it would take more energy to break the bonds of the C2H1010 because the carbon bonds are so prominent.
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