Volts * Amps = Watts
220V * 20 A = 4400 Watts
BUT!!!
You don't want to run a generator at 100% capacity for very long; that should be considered peak conditions only and the generator should be run at 80% or less.
The generator will last a lot longer if you run it at 50% capacity (in other words, a generator with 8800 Watt capacity would be a good place to start)
I am assuming that the voltage for this service is 120/240 volts. For a different service voltage exchange the 240 volts with the required service voltage. The formula you are looking for is Watts = Amps x volts = 100 x 240 = 24000 or 24000/1000 = 24 KVA x pf. The most likely single phase generator would be 25kW as it is a standard size.
Generators are rated in kilowatts. The equation used to find kW is kW = I x E x 1.73 x power factor /1000. kW = 100 x 440 x 1.73 x .89/1000 = 67.7 kW.
A 70 kW generator would be recommended for this size load.
That power is 22 kW so the minimum generator size would be 22 kVA.
That load is 72 kVA so you would need a generator of 80 kW driven by a motor of 120 hp. For continuous use you would need a 100 kW generator and 150 hp motor.
Assuming a 240 v single-phase supply:
For 100 amps, 100 x 240 VA or 24 kVA
For 200 amps, 200 x 240 VA or 48 kVA
75 Amps theoretically Need to know if the generator is 3 phase or single phase.
The equation that you are looking for is I = W/E. Amps = Watts/Volts. The generator has the capacity to supply 25 amps. Of course the load is what governs the amount of amperage drawn. Any load greater than 25 amps will load the generator down and probably trip the generator's breaker.
Answer for UK, Europe and countries running a 50 Hz supply service.A farm that takes a 700-amp supply on 3-phase 415 volts is a big farm drawing 500 kVA so it really needs a 750 kVA generator that would be expected to use 60-70 gallons of diesel per hour. It should be noted that 3 phase 415 volts is a 50 Hertz generated supply.At lower voltages the power drawn would be less, but the answer is independent of the supply frequency.Answer for countries running a 60 Hz supply service.A farm that takes a 700-amp supply on 3-phase 208 volts is a farm drawing 250 kVA that needs a 300-350 kVA generator. It would be expected to use 30-40 gallons of diesel per hour.
to calculate the motor full load current one should know motor power factor, supply voltage and phase of supply. Assuming your motor is with 0.85 pf and 3 phase, 415V source then P = (Sqrt3)*V*I*pf 18500 = 1.732*415*0.85*I hence I = 30.2A
An 11,000 volt three-phase supply has a voltage of 6351 from live to neutral, when there is a neutral wire.
No.
75 Amps theoretically Need to know if the generator is 3 phase or single phase.
The equation that you are looking for is I = W/E. Amps = Watts/Volts. The generator has the capacity to supply 25 amps. Of course the load is what governs the amount of amperage drawn. Any load greater than 25 amps will load the generator down and probably trip the generator's breaker.
How much current equipments are drawing from three phases (combined or individual) is called three phase load and how much supply we are getting from source is called three phase supply. Ex. In INDIA single phase supply is 220 volt ac with neutral. So in three phase supply all RYB phases should be 220 volts ac with neutral individually. If we calculate with phase to phase than it shoulb be 415 volts ac.
Answer for UK, Europe and countries running a 50 Hz supply service.A farm that takes a 700-amp supply on 3-phase 415 volts is a big farm drawing 500 kVA so it really needs a 750 kVA generator that would be expected to use 60-70 gallons of diesel per hour. It should be noted that 3 phase 415 volts is a 50 Hertz generated supply.At lower voltages the power drawn would be less, but the answer is independent of the supply frequency.Answer for countries running a 60 Hz supply service.A farm that takes a 700-amp supply on 3-phase 208 volts is a farm drawing 250 kVA that needs a 300-350 kVA generator. It would be expected to use 30-40 gallons of diesel per hour.
The process of obtaining 220 volts from 380 volts is quite simple. 380 volts is a three phase four wire system voltage. The 220 volts is obtained by taking the sq. root of 3 which equals 1.73 and dividing it into the phase voltage. 380/1.73 = 220 volts. This holds true with any three phase four wire voltage system. 208/1.73 = 120 volts, 415/1.73 = 230 volts, 480/1.73 = 277 volts and 600/1.73 = 347 volts. This lower voltage is present on any of the three phase legs of the three phase system to the neutral which is grounded on a wye connection.
220 volt single phase from 480 volt 3 phase that one wire taken one phase and second wire connected in earth point. we get 220 v The above answer is incorrect, one phase from a three phase 480 volt system will give you 277 volts to ground. You must use a transformer to get the voltage you need.
No, you will not obtain 230 volts. From a wye connected three phase 480 volt supply, 277 volts can be obtained from one phase leg and the neutral on the wye connection. 480 volts/1.73 (sq. root of 3) = 277 volts.
No, you can not you change the wiring of a single phase appliance of 2.4 kw that works on 240 to 400 volts 3 phase 60 Hz supply. They are two different electrical systems.
form_title=Well Pump Installation form_header=12353 Are you in need of single or three phase power?*= () Single phase () Three phase () Don't Know Do you know the voltage of you power supply?*= () 155 volts () 208 volts () 230 volts () 460 volts () Don't Know () Other
to calculate the motor full load current one should know motor power factor, supply voltage and phase of supply. Assuming your motor is with 0.85 pf and 3 phase, 415V source then P = (Sqrt3)*V*I*pf 18500 = 1.732*415*0.85*I hence I = 30.2A
The formula you are looking for is , A = kva x 1000/Volts.