You won't get a remainder of 1 if you divide by 1. If you want the same for all the numbers from 2-12, you must get a common denominator of all the numbers from 2-12. Any common denominator might do, so you could just multiply all those numbers together; or (to get all solutions) get the least common denominator. Next, find a multiple of this common denominator that has 13 digits, and add one to the result. That's it!
Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.
100
111
No, 110 is not a multiple of 3. A multiple of 3 is any number that can be divided evenly by 3, with no remainder. When 110 is divided by 3, the result is 36 with a remainder of 2.
The greatest possible remainder for 76 is to be divided by 2 leaving the result of 38. Thank you!
Probably many answers, but for example 100 / 8 = 96 remainder 4
The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.
That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.
9
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2.
Regardless of the dividend (the number being divided), no divisor can produce a remainder equal to, or greater than, itself..... dividing by 4 cannot result in a remainder of 5, for example, Therefore the only single-digit number which can return a remainder of 8 is 9. 35 ÷ 9 = 3 and remainder 8
36.75