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X is the 1st integer

X+1 would be the 2nd

X+2 would be the 3rd

X+(X+1)+(X+2) = 132

3X+3=132

3X+3-3=132-3

3X=129

X=129/3 = 43

So the consecutive integers are 43, 44, 45

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Q: What three consecutive integers have a sum of 132?
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