The sum is 22 times the sum of the three digits.
it is 10
There is no number. 100 is the only one that has a hundreds digit. It's impossible.
Mental math like if 12 into 72 it will not be a double digit if you divide 100 by 10 it will be double digits. Most times if you have a tripple digit number and divide it by double digit the answer will be a double digit.
The first digit has to be in the set [1-6] because, if it were zero, it would not be a three digit number. The number of combinations, not using duplicates, of three numbers from the set [0-6] is 6 times 6 times 5, or 180.
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27
what is the greets possible 9 digit number that uses each of the digits 1-3 times
To count the number of times a digit occurs in an integer, start by initializing an array of ten counts of digits, such as int digits;Then, in a loop while the number is non zero, increment the element in the digits array that corresponds to the units digit, and then divide the number by ten, such as digits[number%10]++ and number/=10;int digits;int i;int number = some number;for (i=0; ido (digits[number%10]++; number/=10) while (number != 0);
They are the same because they are both multiplication. They also can be the same if the two digit number times by the one digit number equals a three digit number. They are different because the 3 digits number will obviously produce a higher product.
15 1 x 5 = 5, and 5 x 3 = 15