# What two digit number is three times the sum of its digits?

**27**

3(**2**+**7**)=**27**

### How do you make a program that counts how many times each digit occured in the integer?

To count the number of times a digit occurs in an integer, start by initializing an array of ten counts of digits, such as int digits[10]; Then, in a loop while the number is non zero, increment the element in the digits array that corresponds to the units digit, and then divide the number by ten, such as digits[number%10]++ and number/=10; int digits[10]; int i; int number = some number; for (i=0; i<10; i++) digits[i]=0…

### How many 4 digit combinations can be made from these 3 numbers 2-6-5?

Assuming you're allowed to repeat numbers, the answer is 81. For each digit, you have three choices: 2, 5, and 6. So there are three one-digit numbers you can make, and each one digit number can be combined with any of three other digits to make a two-digit number, giving 9 (3 times 3) possibilities. Now you can take any of the nine two-digit numbers as the tens and ones places in the four-digit number…

### What 3 digit number ia 3 times the sum of its digits?

Without digging too deeply into this question, we can see immediately that it has no solution. -- The largest possible sum of 3 digits is (9 + 9 + 9) = 27 -- 3 times (the largest possible sum of 3 digits) is (3 x 27) = 81 -- 3 times the largest possible sum of 3 digits is smaller than any 3-digit number.

### The sum of the digits in two- digit number is 15 If the number is 6 more than 15 times the units digit find the number?

If the sum of the digits in a two-digit number is 15, and the number is 6 more than 15 times the units digit, the number is 96. Let A and B be the digits. (A is the tens digit and B is the units digit) A + B = 15, therefore A = 15 - B 10A + B = 15B + 6 Substituting for A, and solving for B... 10(15 - B) +…

### In a certain two-digit number the tens' digit exceeds the units' by 5 What is the number if it is known that the number is equal to ten times the sum of the digits?

The two digit numbers in which the tens digit is five greater than the units digit are: 50 61 72 83 94 The number we are looking for is ten times the sum of its digits, and so must be a multiple of 10. The only one of the above numbers which fits this is 50, as 5 is five greater than 0, and 50 = 10 x (5+0).

### How do you figure out how many times 5 digit numbers can be made by using the numbers 12345 without repeating a number twice?

The first digit can be any one of 1, 2, 3, 4 or 5. So you can choose the first digit in 5 ways. Having done that, you have only four unused digits. So you can chosse the second digit in 4 ways. Now then you have only three digits left so the third digit can be chaosen in 3 ways and so on. Total number of ways: 5*4*3*2*1 = 120

### What The rule of a number divide by 8?

If you mean what is the divisibility rule for the number 8: There are two: 1. For any power n of 2 the last n digits of the number must be divisible by 2 to the power n. 8 = 2³ → If the last 3 digits are divisible by 3, then so is the whole number. 2. Add the last (ones) digit to 2 times the tens digit to 4 times the hundreds digit…

### How does the value of a decimal change as you move to the left or the right in a place value chart?

As the digits are moved left, the digit in the tenths column goes into the units column, the digit in the hundredths column goes into the tenths column, etc; each digit is ten times its previous value, thus moving the digits to the left multiplies the number by 10. Similarly moving the digits to the right: the digit in the units column goes into the tenths column, the digit in the tenths column goes into…

### How are you using the distributive property when you multiply one 2 digit number by another?

When you multiply a two digit number by another, you use the distributive property because you basically are taking the tens digits times both the other tens digit and the ones digit, then the ones digit times both the other tens and other ones digits. That sounds confusing, I know, but I'll explain. If you're taking 12 times 25, you are basically doing the problem (10+2) x (20+5). You take ten times twenty, then ten…

### Who mad the atomic bomb?

All round numbers are divisible by 1 If it's an even number (i.e. the last digit is a 0, 2, 4, 6 or 8), then it's divisible by 2. If the sum of digits is divisible by three, then the number is divisible by three (e.g. the number 2821446 is divisible by three, because 2 + 8 + 2 + 1 + 4 + 4 + 6 equals 27, which is also divisible by three…

### What are the divisibility rules for 1-10?

All round numbers are divisible by 1 If it's an even number (i.e. the last digit is a 0, 2, 4, 6 or 8), then it's divisible by 2. If the sum of digits is divisible by three, then the number is divisible by three (e.g. the number 2821446 is divisible by three, because 2 + 8 + 2 + 1 + 4 + 4 + 6 equals 27, which is also divisible by three…