Phosphoric Acid dissociates to give off 3H+ ions, meaning that one mole of Phosphoric acid reacts with three mols of sodium hydroxide.
Using the equation n = c x v
n = 0.1 x 0.05
=0.005 mols of OH ions in the solution
therefore there are 0.005/3 = 0.00167
So the volume of phosphoric acid -
v = n/c
v = 0.00167/0.2
v = 0.00835 l
= 8.4ml of Phosphoric Acid reacts completely with Sodium hydroxide
Sodium phosphate is obtained.
4m
Combine phosphoric acid and sodium hydroxide, very carefully, this will leave you with what you can utilise as sodium phosphate.
Na2HPO4, Na3PO4,NaH2PO4
None! Trisodium phosphate is the end produce of neutralizing phosphoric acid with sodium hydroxide. So, no further reaction is possible.
98g of phosphoric acid require 120g of sodium hydroxide to produce sodium phosphate so 150g phosphoric acid will require = 120/98x150= 183.67g sodium hydroxide.
Molarity, not moles. Simple equality will do here.(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)0.200X = 0.5X = 2.5 milliliters sodium hydroxide solution needed====================================
Sodium phosphate is obtained.
The molarity is 0,125 M.
Hydrochloric acid Sulfuric acid Phosphoric acid Sodium hydroxide Calcium hydroxide Potassium hydroxide
Yes, indeed!
4m
Combine phosphoric acid and sodium hydroxide, very carefully, this will leave you with what you can utilise as sodium phosphate.
Na2HPO4, Na3PO4,NaH2PO4
With a calculator. That is the easiest way.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
.13 (Plato)