The volume of gas that 3.5 moles of oxygen occupy can be easily found using the relationship of PV=nRT where P is the pressure, V is the volume, n is the moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
According to the Gas Laws equal number of all gases occupy equal volume given that the pressure and temperature are constant. So at STP (Standard Temperature and Pressure), 1 mole of all gases occupy 22.71 L. Standard Temperature is 0 degree Celsius whereas standard pressure is 1 bar.
Therefore 3.5 mol CO(2) at STP will occupy = 22.71 * 3.5 = 79.485 L of volume.
The volume of 3 mols of ideal gas at NTP is 3*22,4 litres = 67,2 dm^3.
one mole of a gas at s.t.p has the volume 22.414 litres so 3 moles of oxygen gas occupy 67.242 litres volume.
You use the equation PV=nRT at STP, P=1atm and T=273K, therefore:
1*V = 1.5*.08206*273
V=33.6L
At standard temperature and pressure (STP), 1 mole of any gas occupies about 22.4 liters of space. If you have 3.75L of a gas, then 3.75/22.4=0.17 moles.
1 mole of any gas at stp occupies a volume of 22.4dm3. So 3.5 moles will occupy 78.4dm3.
1,75/21,4 = 0,0818 moles
The volume is 78,449 L.
71.7248
fly
Not only that, but it's one of lightest, or possibly the lightest, gas in the world. I'm a nerd, so you can trust me.
1 mole of any gas at STP occupies 22.4 liters. Thus, 2 moles propane will occupy 2 x 22.4 L = 44.8 liters.
1 standard volume of 1 mole of any gas @ STP is 22.4 LSo the # of moles in a 1 L sample will be:1 L*(1 mol/22.4 L) = 0.04464 molSince you already know the mass of the gas @ STP, the molar mass will be mass/#moles1.92 g/ 0.04464 mol = 43.01 g/mol
Yes.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
According to the Ideal Gas Law, under STP conditions, a mole of an ideal gas occupies 22.4L. Thus, 1.4g He, or 0.35 moles He is equivalent to: 1.4g He x (1 mol He/4.00g He) x (22.4L He/1 mol He) = 0.016L of He
1 mol of any gas has a volume of 22.4 L at STP
Most commonly, this refers to the volume of a gas at Standard conditions of Temperature and Pressure (often abbreviated, STP). This standard allows accurate comparisons of volumes. The volume of a gas (any gas) at STP is 22.4 liters per mole.
1 mole of gas at STP occupies 22.4 liters.
1.799 kg/m3 at 25 Co .
CO2
Because you're in STP conditions, you can use molar volume in a proportion. Molar volume is the volume one mole of an ideal gas will take up at STP: 22.4 liters/mole. To set up a proportion, think: if one mole of a gas occupies 22.4 liters, then 4.0 moles of a gas will occupy x liters.1 mole/22.4 L = 4.0 mole/X Lx = 44.8 liters
The volume is approx. 15,35 litres.
molar volume
Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
Of course. But at STP, any gas has a standard volume of 22.4 Liters.