answersLogoWhite

0

What will be state of water at -25 C?

Updated: 9/25/2023
User Avatar

Sdrall78fb2033

Lvl 1
9y ago

Best Answer

At -25 Celsius, water will be a solid. Converting from Celsius to Fahrenheit, -25 C is -13 F.

User Avatar

Wiki User

9y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What will be state of water at -25 C?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What will be the state oh water at 25 C?

The state of water at -25 C is solid. Water freezes at 0 degrees Celsius.


What is the density of PURE water in its liquid state?

At 25 degrees C the density of water is 1.0 g/mL. If the temperature of the water goes above 25 degrees C the density will drop. If the temperature of the water goes below 25 degrees C the density will rise.


What is the state of phenol at 25 C degrees?

Phenol at 25 C degrees is a solid.


What is the pKa of glucose?

12.28 at 25°C 12.28 at 25°C in water


What is the state of OXYGEN at 25 degrees C?

Pure oxygen is a gas at 25 C, regardless of the pressure.


What state is oxygen at 25 degrees c?

gaseous


What state is copper at 25 degrees c?

Solid.


How is Kw valid?

Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C


What is the velocity of sound in water?

In fresh water, ~1500 m/s at 25°C


What is the physical state of water at -23 C?

At this temperature water is a solid.


How many joules are required to heat 22 g of water from 25 degrees C to steam at 125 degrees C?

The specific heat capacity of water between 25 C and 100 C is 4.1813 J / (g*K). Beyond 100 C, the heat capacity of water is 2.080 J / (g*K) So, it take 4.1813 joules of energy to heat 1 gram of water 1 degree Celsius (Kelvin). Therefore, in order to heat 22 g of water from 25 C to 100 C (75 C), it would require: 4.1813 * 22 * 75 = 6899.145 J And, to heat 22 g of steam from 100 C to 125 C (25 C), it would require: 2.080 * 22 * 25 = 1144 J The combined amount of energy required would be: 6899.145 + 1144 = 8043.145 J


What is the olympic water temperature?

The official water temperature ranges for Olympic-sized pools used for the Olympic games are: Swimming Pools: 25-28 °C Diving pools: Not less than 26 °C Water Polo pools: 25-27 °C Synchronized swimming: 26-28 °C