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What will be the algorithm to input n integers and output the largest one?
Wiki User
∙ 14y ago
var largest : integer
largest = array[0]
for n : integer in array
if n > largest
largest = n
endif
endfor
return largest
Wiki User
∙ 14y ago
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How do you write a program to print the first n multiples of 7?
Algorithm: multiples input: two positive integers, m and n output: print first n multiples of m i = m; for j = 1 to n print i i = i + m; next j
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How do you write a program to print the first n multiples of 7?
Algorithm: multiples input: two positive integers, m and n output: print first n multiples of m i = m; for j = 1 to n print i i = i + m; next j
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What a C function that will compute the K in largest and K in smallest element along with their positions in an array of N signed integers. Assume the following 5 N 50 and 1K?
To compute the largest value in an array, assume that the first element is the largest and store the value. Then traverse the remainder of the array. Each time a larger value is encountered, update the stored value. Once all values are traversed, return the stored value. In pseudocode, this algorithm would be implemented as follows: Algorithm: largest Input: array A of length N Output: largest value in A let largest = A[0] // store first value for index = 1 to N-1 // traverse remaining elements if A[index] > largest then largest = A[index] // update stored value if current value is larger next index return largest To determine the position of the largest value, we alter the algorithm as follows: Algorithm: largest_by_index Input: array A of length N Output: index of the largest value in A let largest = 0; // store index 0 for index = 1 to N-1 // traverse remaining elements if A[index] > A[largest] then largest = index // update stored index next index return largest We can do the same to find the position of the smallest element: Algorithm: smallest_by_index Input: array A of length N Output: index of the smallest value in A let smallest = 0; // store index 0 for index = 1 to N-1 // traverse remaining elements if A[index] < A[smallest] then smallest = index // update stored index next index return smallest To perform both algorithms simultaneously, we need to return two values. To achieve this we can use a simple data structure known as a pair: struct pair { int smallest; int largest; }; Algorithm: range_by_index Input: array A of length N Output: a pair indicating the position of the smallest and largest values in A pair result = {0, 0} // initialise the pair for index = 1 to N-1 // traverse remaining elements if A[index] < A[result.smallest] then result.smallest = index // update stored index else if A[index] > A[result.largest] then result.largest = index // update stored index next index return result
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What is the Black box concept?
A black box is where only the owner of that black box knows the algorithm that makes the mechanism change the input to the output. For example, in algorithmic trading, there is proprietary software that transacts with the incoming data and decides when to buy or sell depending on what the algorithm in that proprietary software states. Each owner of a black box has their own proprietary mechanism to change the input to the output.
