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STP = 273k and 1atm pressure

P1 x V1 = P2 x V2

---------- -----------

T1 T2

P1=1

P2=2

V1=2

V2=?

T1=273

T2=273

1 x 2 = 2(?)

-------- ---------

273 273

? = 1

so the volume halves from 2l to 1l

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14y ago
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12y ago

It decreases in direct proportion to the temperature drop.

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13y ago

It increases

Trust me! I'm a doctor!

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13y ago

(P1V1)/T1 = (P2V2)/T2

[(1 atm)(2 L)] / 273oK = [(2 atm)(x L) / (273oK)

2/273 = (2x) / 273

1=X

1 Liter

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14y ago

1.5 L

from Tara.

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7y ago

The factor is two.

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6y ago

The volume remain unchanged.

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3y ago

loosu koothi enakku answer theriyathu

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11y ago

the same 2

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13y ago

44.8

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Q: If the Kelvin temperature of a gas is doubled what happens to the volume?
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