The mass of 5 mol of ammonia is 85,155 g; the number of ammonia molecules in 5 moles is
3,011 070 428 5.10e24.
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
You would multiply the number of grams x Avogadro's number=number of molecules: (21.6g) X (6.022x10^23)= 1.301x10^25 molecules
Gram mole is the mass of a substance which equal to molecular mass in amu. For ammonia we have one nitrogen atom and three atoms of hydrogen. So the molecular mass in amu will be 14+3 = 17 Now 17 g of ammonia would have 6.023 x 1023 molecules. ie avagadro number of molecules. Hence every 1 g will have (6.023/17) x 1023 So for 32 g it would have (32/17) x 6.023 x 1023 molecules.
Ammonia has a nitrogen with a lone pair and three hydrogens, so shouldn't there be extensive hydrogen bonding between molecules? I mean one hydrogen would attach to a nitrogen from ammonia and the next one would attach to another nitrogen from ammonia, etc
It would not be possible, Ammonia (NH3) is constantly associating and disassociating with Hydrogen (H) to make positively charged NH4. Meaning a pure Ammonia solution will always have extra H molecules there with it.
Using the ideal gas law (using torr instead of atm), we calculate that there would be .046 moles of CO, or 2.7x1022 molecules of carbon monoxide.
To calculate the number of molecules in a given number of moles, we use Avogadro's number, which is approximately 6.022 x 10^23 molecules per mole. Therefore, 4.3 moles of K2SO4 would contain approximately 4.3 x (6.022 x 10^23) molecules, which is approximately 2.59 x 10^24 molecules.
To find the mass of sulfur dioxide (SO₂) that contains the same number of molecules as 2 grams of ammonia (NH₃), you can use the concept of moles and the molar mass. **Find the number of moles of ammonia:** [ \text{Moles of NH₃} = \frac{\text{Mass of NH₃}}{\text{Molar mass of NH₃}} ] The molar mass of ammonia (NH₃) is approximately 17 grams/mol. **Use Avogadro's Number:** According to Avogadro's number, 1 mole of any substance contains the same number of entities (atoms, molecules, etc.), which is approximately (6.022 \times 10^{23}). **Find the number of molecules of ammonia:** [ \text{Number of NH₃ molecules} = \text{Moles of NH₃} \times (6.022 \times 10^{23}) ] **Convert to moles of sulfur dioxide:** Since the number of molecules is the same for both substances, the moles of sulfur dioxide (SO₂) would be the same as the moles of ammonia. [ \text{Moles of SO₂} = \text{Moles of NH₃} ] **Find the mass of sulfur dioxide:** [ \text{Mass of SO₂} = \text{Moles of SO₂} \times \text{Molar mass of SO₂} ] The molar mass of sulfur dioxide (SO₂) is approximately 64 grams/mol. Now, you can substitute the values into the equations to find the mass of sulfur dioxide.
In the equation N2+3H2=2NH3, the amount of ammonia produced from 50g of N would be 16.667g.
125
1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
There are 6.02 x 1023 NH3 molecules in 1 mole of NH3.Therefore 0.850mol of ammonia would have 0.85 x 6.02 x 1023 molecules of NH3.In each NH3 molecule there are 4 atoms (one N and three H atoms).Therefore the number of atoms in 0.850mol of NH3 is4 x 0.85 x 6.02 x 1023 = 2.05 x 1024