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molarity of 5% NaCl solution would be 1.25M.
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What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
What is the molarity of a solution in which 58 g of NaCl are dissolved in 1.0 L of solution?
Almost exactly 1 M - to be exactly 1.0M would require 58.5 g NaCl
What is the molarity of a solution that contains 125 g NaCl dissolved in 4.00 L of solution?
The Molarity of the solution is .901
A solution is made by dissolving 17.52g of nacl exactly 2000 ml what is the molarity of this solution?
concentration or molarity = number of moles/volume number of moles (n) = mass in grams of nacl/relative atomic mass of nacl n=17.52/(23+35.5) n = 0.2994872 mol volume = 2000/1000 = 2dm^3 molarity = 0.2994872/2 =0.15mol/dm^3
What is the molarity of the solution where 0.5 g of NaCl is dissolved to make 0.05 L of solution?
Given: 0.5 g NaCl; 0.05 L of solution.1) Find the molar mass of NaCl.(22.99) + (35.45) = 58.44 g/mol of NaCl2) Convert grams of NaCl to moles of NaCl.(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl3) Use the molarity equation, M = mol / L, to solve for molarity (M).(0.00855578 mol NaCl / 0.05 L) = 0.17 M
What is the molarity of a solution consisting of 0.250 mol NaCl dissolved in 2.25 L of solution?
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
Molarity of a solution of 6 moles mol of NaCl in 2L water?
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
What is the molarity of a solution in which 58 g of NaCl are dissolved in 1.0 L of solution?
Almost exactly 1 M - to be exactly 1.0M would require 58.5 g NaCl
How do you calculate the molarity of the solution of 17.52 grams of Na Cl in a total volume of 2000 ml of solution?
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
What is the molarity of 750 mL of NaCl solution that contains 21.04 g of NaCl?
The answer is 0,514 mol.
A sample of 76g of NaCl is dissolved to make 1L of solution. what is the molarity of the solution?
1.3g
What is A 0.0 percent NaCl Solution?
A 0.0% NaCl solution is a solution with absolutely no NaCl.
What is the molarity of 100mL of solution of water and 11.7g of Na Cl?
There would be 117g of NaCl in 1000 ml or 1 liter. The MWt of NaCl is 58.5 so 117/58.5 is 2.00 - so the molarity is 2.00 moles per liter of NaCl
Equal moles of H2O and NaCl are present in a solution Hence molarity of NaCl is?
I suppose that this situation is not possible.
What is the concentration M of a NaCl solution prepared by dissolving 3.8 g of NaCl in sufficient water to give 245 mL of solution?
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
