PH is equal to -log[ hydrogen ion]. You always have to use the concentration of the hydrogen ions. The concentration has to be in Molarity (moles per liter). If your concentration was actually 10 moles per liter, your PH would be -1. If it was 8 moles per liter, it would have a PH of -.903. The PH can actually go below 0 if you are using a strong acid in a very high concentration, but that would be dangerous.
pH = -log[H+] = -log(8-10) = -log(9.313-10) = 9.0309 = 9.03
Mark this:
If [H+] = 10-8 is meant as concentration value, then the pH = -log[H+] = -log(10-8) = 8.00
By definition pH = -log[H+] so:
pH = -log(1*10-4) = 4.0
[H+] = 10-4 and pH = - log10 [H+] so log10 10-4 = -4 . So --4 =+4 pH = 4 - mildly acidic.
pH 8
eight (8)
pH2
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
The molarity is 0,2.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
The molarity is 0,2.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
The molarity is 0,1 M.
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Molarity is moles per litre. So you have to convert volume to a litre. i.e. 0.5x2 is a litre. so you have to do the same to moles. 5x2 is 10 moles. as this is per litre, it is a 10 molar solution.
The molar mass of MgCl2 is 95.21 g. Therefore 0.96 grams is 0.01008 mol of the substance. So the molarity of the solution is 5.04 x 10-3 M.
Molarity of hydrogen solution equals 2.3 X 10^-4 -log(2.3 X 10^-4) = 3.6 pH
10 to the 4th power is 10,000