The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
If the volume doubles, then obviously the density will be reduced by a factor 2.
If the volume doubles, then obviously the density will be reduced by a factor 2.
If the volume doubles, then obviously the density will be reduced by a factor 2.
If the volume doubles, then obviously the density will be reduced by a factor 2.
Pressure and volume are inversly proportional to each other, so as pressure increases by a factor of two, the volume is halved. See the 'gas laws'.
P1 x V1 = P2 x V2
Where P1= initial pressure and V1 = initial volume
P2 = final pressure and V2= final volume.
PV =nRT
P= pressure
V= volume
n= number of moles
R= gas constant
T = temperature
In a balloon the Pressure won't change (it just balances outside), the temperature won't change and the gas constant is obviously constant so you have:
V = An
Where A is some constant
if n is twice as big so is V, so the volume will double.
A really cunning answer would be to assume a spherical balloon, if V doubles and V = 4/3*pi*r^3 then the radius will increase by cube root(2) = ~26% bigger in radius.
The density of a the expanding gas cuts in half. As density is just matter per volume, if there is the same amount of matter, but the volume doubles, the density is divided by two instead of one.
We assume that the balloon is a closed system, i.e. none of the gas inside is leaking out. In the case of a balloon filled with helium or hydrogen (the atoms and molecules are so small that they diffuse through the wall of the balloon), this is not quite accurate, but over a short period of time it's close enough. Since it is a closed system, the mass remains constant. Density is mass/volume so if volume doubles, the density shrinks to 1/2 the original density. Temperature doesn't matter except as the reason that the volume increased.
Density = Mass / Volume The amount of matter in the balloon does not change when it is heated and the volume doubles so the result is the density is halved.
If the volume doubles, then obviously the density will be reduced by a factor 2.
Density is defined as mass divided by volume, and the mass doesn't change. You should be able to figure it out from there. In any case, the density will decrease by a factor of 2.
it becomes low
the mass of the balloon increases because the size of the balloon has increased. :)
The gas will expand as it is heated.
Heated gas has a lower density than environmental air.
the heat makes the molecules inside the balloon travel faster, pushing outward on the balloon. This, the balloon expands when heated
It is reduced by haft
it becomes low
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
The air becomes less dense as it expands making the balloon appear to self inflate.
No it decreases
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
they pop
the mass of the balloon increases because the size of the balloon has increased. :)
It is reduced by haft
The gas will expand as it is heated.
increases