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When any number is multiplied by 6 and the digits of the answer are added the sum will be divisible by 6?
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Dawson Beatty
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What is a two digit number whose two digits added together equal 42 and multiplied together equal 82?
A two digit number whose two digits added together equal 42 and multiplied together equal 82
Is 5715 divisible by 2 3 5 9 or 10?
5715 is not divisible by 2: the last digit is not an even number or 05715 is divisible by 3: as the last two digits when added together is a multiple of 35715 is divisible by 5: as the last digit is a 5 or 05715 is divisible by 9: as if u added all the digits of the number it will be divisible by 9, in this case 5 +7+1+5=18 and 18 is a multiple of 95715 is not divisible by 10: as the last digit is not a 0
Is 5278 divisible by3?
Add up the digits---5+2+7+8 22 which is NOT a multiple of 3 so it is NOT divisible by 3. == Here is a list of the divisibility rules: 2 If the last digit is even, the number is divisible by 2. 3 If the sum of the digits is divisible by 3, the number is also. 4 If the last two digits form a number divisible by 4, the number is also. 5 If the last digit is a 5 or a 0, the number is divisible by 5. 6 If the number is divisible by both 3 and 2, it is also divisible by 6. 7Take the last digit, double it, and subtract it from the rest of the number;if the answer is divisible by 7 (including 0), then the number is also. 8If the last three digits form a number divisible by 8,then so is the whole number. 9 If the sum of the digits is divisible by 9, the number is also. 10 If the number ends in 0, it is divisible by 10. 11 Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)If the result (including 0) is divisible by 11, the number is also.Example: to see whether 365167484 is divisible by 11, start by subtracting:[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. 12 If the number is divisible by both 3 and 4, it is also divisible by 12. 13Delete the last digit from the number, then subtract 9 times the deleteddigit from the remaining number. If what is left is divisible by 13,then so is the original number
How can you tell if a number is divisible by 9?
Any number which is divisible by 9 contains digits which, when added together, are equal to 9 or a multiple of 9. For example, 63 is divisible by 9 because 6 + 3 = 9. 288 is divisible by 9 because 2 + 8 + 8 = 18 and 18/9 = 2.
What number should be added to 39065 to make it divisible by 9?
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341
Is 1038 a prine number?
Nope - 1038 is an even number and thus is divisible by 2. Its digits added together total 12 - which is divisible by 3... therefore the original number is also divisible by 3 !!
What is a two digit number whose two digits added together equal 42 and multiplied together equal 82?
A two digit number whose two digits added together equal 42 and multiplied together equal 82
Is 140 divisible by 3?
Nope - For any number to be divisible by three, the sum of the digits added together must ALSO be divisible by three. In this case 1+4=5.
Is 5715 divisible by 2 3 5 9 or 10?
5715 is not divisible by 2: the last digit is not an even number or 05715 is divisible by 3: as the last two digits when added together is a multiple of 35715 is divisible by 5: as the last digit is a 5 or 05715 is divisible by 9: as if u added all the digits of the number it will be divisible by 9, in this case 5 +7+1+5=18 and 18 is a multiple of 95715 is not divisible by 10: as the last digit is not a 0
Is 342 divisible by 5 or 6?
342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.
Is 4339 divisible by 3?
No. To find if a number is a factor of 3, add the number's digits. If the resulting number is a multiple of 3, then the original number is a multiple of 3. In 4339, the digits of the number added together is 19, which is not a multiple of 3.
Is 5278 divisible by3?
Add up the digits---5+2+7+8 22 which is NOT a multiple of 3 so it is NOT divisible by 3. == Here is a list of the divisibility rules: 2 If the last digit is even, the number is divisible by 2. 3 If the sum of the digits is divisible by 3, the number is also. 4 If the last two digits form a number divisible by 4, the number is also. 5 If the last digit is a 5 or a 0, the number is divisible by 5. 6 If the number is divisible by both 3 and 2, it is also divisible by 6. 7Take the last digit, double it, and subtract it from the rest of the number;if the answer is divisible by 7 (including 0), then the number is also. 8If the last three digits form a number divisible by 8,then so is the whole number. 9 If the sum of the digits is divisible by 9, the number is also. 10 If the number ends in 0, it is divisible by 10. 11 Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)If the result (including 0) is divisible by 11, the number is also.Example: to see whether 365167484 is divisible by 11, start by subtracting:[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. 12 If the number is divisible by both 3 and 4, it is also divisible by 12. 13Delete the last digit from the number, then subtract 9 times the deleteddigit from the remaining number. If what is left is divisible by 13,then so is the original number
What are the divisibility rules for 1-13?
14
The factor of every palindrome with an even number of digits?
Every palindrome with an even number of digits is divisible by 11. The easiest way to see this is to recall the divisibility rule by 11: if a number X is written as ABCDEFG... (here A,B,C, ... are digits), then it's divisible by 11 if and only if the sum A-B+C-D+E-F+G-... is divisible by 11. In a palindrome with an even number of digits, each digit will appear in an odd position and in an even position, so when we calculate this sum, it will be added once and subtracted once, canceling. Since all the digits cancel, the sum A-B+C-D+... will be 0, which is divisible by 11. So the original number ABCD....DCBA was also divisible by 11.
Is 6111 is a prime or composite number?
Using the divisibility rules, we can tell that 6111 is divisible by 3 (The digits when added together equal 9, which is divisible by 3, so 6111 is divisible by 3). Since 3 is a factor, it is a composite number (a number with more factors than 1 and itself).
Is 4725 divisible by 3?
Yes it is. The sum of all the digits added together is divisible by 3 - therefore the original number is too. Hint: it's more than 1550 but less than 1600 !
3924 is divisible by 3 false true?
3924 is divisible by 3 as the digits added together 3+9+2+4=18 is divisible by 3
