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Answered 2012-08-23 17:13:04

Remains true. But this does not apply to square roots.

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9x2 = 81 x2 = 9 <-- Divide both sides by nine x = 3 <-- Square root both sides All in all this is NOT a difficult equation.

If you are solving for y, it is fine. If you are solving for x, divide both sides by x and the equation should be x = y/x

An equation has two sides, and each of these sides is equal to the other.

Equal quantities may be added to both sides of a linear equation.

Divide both sides of the equation by 3, resulting in a on the left side and 1022/3 on the right. (Simplify as you wish.)

In an equation, the left side has the same value as the right side. The importance of doing the same thing to both sides is to keep the value of both sides the same so the equation does not change.

Raising both sides can throw away information. Take x=y: these two items are equal, right? Now look at x^2 = y^2 -- we have discarded any distinction between positive and negative values.

It follows from the multiplication property of equality. Dividing both sides of an equation by the same number (not by zero, of course) is the same as multiply both sides of the equation by the number's reciprocal. For example, dividing both sides of an equation by 2 is the same as multiplying both sides by 0.5.

If both sides of an equation are not equal, it won't be an equation any more! In solving equations, the strategy is to change both sides in the same way, so that an 'equivalent' equation is produced. An equivalent equation has the same solution as the original equation. You are aiming for an equation in which the variable is alone on one side. The quantity on the other side is the solution.

Whatever is done to one side of an equation must be done to the other side in order to keep the equation balanced.

(a + b)² = a² + b². If you expand the left side, you have a² + 2ab + b² = a² + b². Subtracting a² and b² from both sides, you have: 2ab = 0. So if either a=0 or b=0 the equation is satisfied.

if you want to "solve" this equation, you need an equals sign somehwere! For example, if the problem was 2x - 52=5 then you could solve. You add 52 (or 25) to both sides so the equation becomes 2x = 30. Then you divide both sides by 2 to get x=15

An algebraic equation is a mathematical equation in which one or both sides is an algebraic expression.

That both sides of the equation must be equal

When in doubt always square both sides of the equation.

I assume you want an equation with a solution of 212. Just write: x = 212 If you want something more fancy, do something to both sides of the equation - this is basically the opposite of what you do to solve an equation. For example, you can multiply both sides of the equation by some number (the same on both sides, of course), add the same number to both sides, square both sides (note that this will most likely add additional solutions, that are not solutions to the original equation), etc. If you already know a bit about more advanced math, you can take logs or antilogs on both sides, take sines or inverse sines on both sides, etc. (this, too, may introduce additional solutions).

do you mean math equation? If you add a number to both sides of an equation you do not change it. That is called algebra

If you are trying to solve the equation -10x plus 12 equals zero the equation would look like this: -10x+12=0. You would begin by subtracting 12 from both sides of the equation to isolate the variable x on one side leaving you with: -10x=-12. Next you would divide both sides of the equation by -10 resulting in: x = 1 and 1/5.

Subtract 2 from both sides of the equation: 7x + 2 - 2 = -19 - 2 7x = -21 Divide both sides of the resulting equation by 7: 7x/7 = -21/7 Solution: x = -3 How much is 5x + 15?

First you square root everything on both sides to cancel the squares. 30+B=78 Then subtract 30 from both sides to get B=48. So the answer is B=48

Without an equality sign it is not an equation but if you mean 18+m = 27 then by deducting 18 from both sides of the equation m = 9

Multiply both sides ofthe equation by the 'denominator' of the fraction.

Square root of x = 29 can be rearranged by squaring both sides of the equation. That would leave you with: x = 29^2 (or 29 squared) So, work out what 29 squared is and that's what x is equal to.