P1 = V I1, Therefore, if P2=0.5*P1, then
I2=0.5*P1/V, or 0.5*I1
and if P3=2*P1, then
I3=2*P1/V, or 2*I1
In other words, current is proportional to power and inversely proportional to voltage.
Since current is, by Ohm's Law, equal to voltage divided by resistance, then doubling both will result in no net effect to the current.
If the resistance is doubled, the current will be diminished, if the resistance is halved, the current will be increased.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
The circuit resistance is likely to gradually drop and in such case it will cause the circuit to burn down.
The answer depends entirely upon the scenario. Are you dealing with AC or DC? Does your circuit contain passive components or both passive and active components?For example, if you a simply dealing with a resistive DC circuit, you can derive your answer from Ohm's law, V = IR. Rearranging for current, I = V/R, so if you double the voltage, the current is subsequently doubled.
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
It is halved. coz voltage=current * resistance
That has no effect on the resistance. The current doubles also.
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
I = E/R If resistance is constant, then current is directly proportional to voltage. Double the voltage ===> the current will also double.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
If you don't change the voltage between the ends of the circuit,then higher resistance in the circuit means lower current (amps).
current decreases and resistance increases
Flow of current decreases proportionately.
Since resistance is the ratio of voltage to current, we can say that halving the resistance will result in twice the current.
As the resistance is reduced across the same voltage, the current increases.