It gets heated up and glows spreading the light
No power is used. The lamp in the light fixture is the load of the circuit. The load resistance is what makes the current flow. When the current flows through the filament's resistance, heat and light are generated. With no lamp in the fixture, the circuit's voltage potential is still at the socket contact points and if touched could cause you a shock. This is a good reason to shut the fixture off at the switch when removing the burnt out bulb and replacing it with a new one.
when the coil wire in the bulb has electricity passing through it the wire heats up to then create light.
The electrical current comes into the bulb from the metal side,flow through the filament ,and out the tip.
A fused bulb does not glow because the filament of a fused bulb is broken. Since current can't flow through the filament, it can't get hot enough to glow.
No. A light bulb is a bulb that contains a filament that gets hot when electric current is passed through it.
If the bulb lights up then electricity is passing through the bulb. If the bulb doesn't light up then electricity is not passing through.
it stays there. the electricity travels back and forth through the filament until you turn the lighbulb off.
It is the extremely thin wire inside the bulb. It is so thin that when the electricity goes through produce light, when that filament breaks the bulb is not good.
No, the broken filament breaks the connection which electricity needs to complete the circuit.
Assuming it's a filament (incandescent) bulb, no. When a bulb burns out, the tiny wire in the bulb is broken, and the electricity can no longer pass through the bulb. It's the same as if it was switched off.
A light bulb works by passing electricity through a long, thin piece of metal that is called a filament. The electricity heats up the filament much like an electric stove heats up its elements. The heat, through black body radiation, causes the filament to emit light. But, the heat also stretches and thus weakens the filament. Over time the weakening will break the filament along the heated portion and this is called "burning out" in common language.
Technically the bulb does not light, it is but a housing for the filament and electrodes. It is the filament that gives off the light as it is heated by the electricity passing through it. The bulb helps to scatter the light in equal proportions.
Electricity through a thin wire (filament) makes it glow, which is prevented from burning through the wire by gas inside the bulb.
Heat, which then produces light.
No it does not FORM it. It converts chemical energy in the battery cell into electrical energy which is then passed through a thin wire called the filament at the bulb. The filament lights up when electricity passes through it, thus giving out light.
The filament is made of tungten and these 'wires' (filament) conduct electricity.
The filament in a light bulb forms resistance so that heat can happen. The electricity then converts to light energy and heat energy so that the light will shine.