the modulation system is of FM
1200/sqrt(2) = 848.5 (rounded)
For to keep the resonant frequancy constant L*C has to stay same. Lets say if you double L you have to divide C by 2 to keep the same resonant frequency. If only L increases Resonant frequency decrease, this is same for C.
It is halved. coz voltage=current * resistance
DATE: 17-MAY-12 THE CAPACITIVE REACTANCE VARIES INVERSELY WITH THE AMOUNT OF THE PRODUCT OF MAGNITUDE OF THE SUPPLY FREQUENCY, TWICE THE VALUE OF CONSTANT PI AND THE MAGNITUDE OF CAPACITANCE. IN OTHER WORDS, EVERY TIME YOU INCREASE ANY OF THESE FACTORS OR IF SAY YOU FIX THE VALUE OF CAPACITANCE TO SAY 1 MICROFARAD AND OTHER FACTOR (i.e. 2 x PI) AS CONSTANT ALSO, BUT THEN WHEN DOUBLING THE FREQUENCY, SO THEN THE EFFECT TO THE CAPACITIVE REACTANCE WILL BE INVERSELY OR HALVED. THE MORE YOU INCREASE THE FREQUENCY, THE SMALLER THIS VALUE WILL BE. WHICH IN EFFECT ALLOWING MORE HIGH FREQUENCY CURRENT OR VOLTAGE TO PASS THRU THE CIRCUIT. AND THE REVERSE IS TRUE, MEANING ONCE YOU ALLOW LOW FREQUENCY CURRENT, THEN THE CAPAICTIVE REACTANCE WILL INCREASE AS A RESULT. BY FMSJr. / ABU DHABI, UAE
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
It's Angle modulated system where the amplitude remains constant & frequency & phase varies with respect to modulating signal.
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed
Frequency = Velocity divided by wavelength. So if frequency is doubled that means velocity is doubled but the wavelength is halved. You can see this by keeping wavelength a constant : If Frequency =1 and Wavelength= 1 1= Velocity/1 Velocity=1 If Frequency =2 and Wavelength= 1 2= Velocity/1 Velocity =2 OR keeping Velocity constant: If Frequency =1 and Velocity= 1 1= 1/Wavelength Wavelength =1 If Frequency =2 and Velocity= 1 2= 1/Wavelength Wavelength=1/2
The frequency is the reciprocal of the period. If the period is doubled, the frequency will change by a factor of 1/2.
the wavelength of the wave get smaller, decreases because the frequency is doubled, increasing..vise versa.
More than doubled. The stopping voltage is the photon energy minus the work function: hv - W Doubling the photon energy creates a new stopping voltage of: 2 hv - W > 2 (hv - W)
Impedance of a coil or a capacitor does depend on the excitation frequency,but resistance has no relationship to frequency.
If the frequency is doubled then the wave length and period will be halved because in the same time that the original wave occurred, you will now see 2 waves. .here is NO change in its its speed.
The speed halves.
The speed halves.
The speed halves.