The size of a vector cannot be fixed because a vector is a wrapper for a dynamic array where resizing occurs automatically (by virtue of the vector class). So, even if you reserved enough memory for n elements in advance, the vector will resize automatically as soon as you push more than n elements. A normal dynamic array does not resize automatically (you have to manually resize the array in order to accommodate more elements than you've allowed), and is therefore more suitable for a fixed size dynamic array. However, if you embed a vector in your own class wrapper (such as fixed_vector), you can reserve n elements in the vector via the constructor, and subsequently control how many elements are pushed onto the vector. Once n elements are pushed, any subsequent elements can be ignored, perhaps raising an exception for added safety.
Try 'sizeof', it will return the size in bytes.
In C++ NULL is defined as 0. It's a design failure, will be fixed with a new 'nullptr' keyword.
There is no preset limit on the size of an else-if ladder in C++. It depends on compiler design and available memory.
Use sizeof( ).
arrays in C are the data types which have collection of same type of data together store a fixed-size s of elements .
conditional operator , size of operator , membership operator and scope resulation operator can not be overload in c++
type variable {[optional array size]} {= optional initializer};
Generally, a array is fixed in size. With some libraries, however, they are extensible, either by reallocation/copying strategies (C/C++/STL), or by linking/referencing strategies (JAVA).
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b+b+b+c+c+c+c =3b+4c
c + c + 2c + c + c = 6c
You could just use memcpy(3), using sizeof() to get the object size.