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When y equals x squared plus k and both x and k are integer how to quickly converge y to be a perfect integer square by varying x where eg 225 is solution for y when k equals 161 and x equals 8?
Wiki User
∙ 13y ago
This is a hyperbola. It is best approached using Fermat's factorisation method. See
or Google wikepedia
Wiki User
∙ 13y ago
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That can be figured out quickly by trial and error. Since I assume you want an integer, the answer is either 21 or 22 (that is, both work).That can be figured out quickly by trial and error. Since I assume you want an integer, the answer is either 21 or 22 (that is, both work).That can be figured out quickly by trial and error. Since I assume you want an integer, the answer is either 21 or 22 (that is, both work).That can be figured out quickly by trial and error. Since I assume you want an integer, the answer is either 21 or 22 (that is, both work).
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