Suppose your age now is Y
So 3*(Y + 3) + 4*(Y + 4) = 8*Y
That is, 3Y + 9 + 4Y + 16 = 8Y
or 7Y + 25 = 8Y
so that Y = 25
In two years time you will be Y + 2 = 27
Penny is five years old. In 10 years she will be 15, which is three times her current age.
5(x + 5) + 6(x + 6) = 12x5x + 25 + 6x + 36 = 12x11x + 61 = 12x61 = 21x - 11xx = 61i.e. you are currently 61. In two years, you would be 63.
Let a represent the current age. From the statement of the problem, a + 5 = 3(a - 3); a + 5 = 3a -9; 14 = 2a; a = 7.
Roger's age is 4.ExplanationRoger is 4 years old. That's two times the age of his sister, who is 2 years old.Last year, Roger was 3 years old, and his sister was 1; Therefore making Roger 3 times his sister's age.
In 2010 your age will be 58 years. (2010 minus 1952 = 58).
Penny is five years old. In 10 years she will be 15, which is three times her current age.
5(x + 5) + 6(x + 6) = 12x5x + 25 + 6x + 36 = 12x11x + 61 = 12x61 = 21x - 11xx = 61i.e. you are currently 61. In two years, you would be 63.
The idea is to add 30 to your current age.
3
1021 seconds = 31,688,087,810,000 years (rounded)That's something like 2,300 times the current estimated age of the universe.
Let a represent the current age. From the statement of the problem, a + 5 = 3(a - 3); a + 5 = 3a -9; 14 = 2a; a = 7.
Chloe is 15 3 x 15 = 45 - 9 = 36 (moms current age) 15 +5 = 20 (Chloe's age in 5 years) 36 + 5 = 41 (mom's age in five years)
The current projections of men and women more than sixty years of age is about 20 percent.
50 years old
18 years old
33
My prediction is that it will decay after a half-life of more than 10^30 years. That is more than a quintillion times the current age of the universe.