Wiki User
∙ 8y agoWant this question answered?
Be notified when an answer is posted
ject weighs maximum in air ,hydrogen ,water, oil?
Weight is dependant upon gravity and the relationship to large bodies of mass such as planets. However, if you were to be put into a vacuum on the surface of the Earth, you would way less. There is air pressure pushing down on you and that would add some weight. It also pushes up on parts of you. The difference is not likely to be very significant, but it should be measurable. However, I don't volunteer to be the person in the vacuum chamber! I am not a scientist, but I believe that you would weigh very slightly more in a vacuum. Think of our atmosphere as being a liquid of very low density compared with water. An object that floats in water displaces water in the amount of the object's weight; if you put a scale under a floating object, the scale registers the object's weight as zero. A perfectly bouyant object has the same density (specific gravity) as water, and as such will have a substantial weight if measured on land. But it will have no weight if weighed in water. An object that sinks in water will have weight, but it will weigh its land weight minus the weight of water displaced by its volume. This should be the same for a person (in a pressure suit, of course). The person will not be bouyed up at all by the atmosphere.
This phenomenon is called buoyancy and is caused by the object displacing water equal to its volume. If the weight of the object is less than the weight of this displaced water, then the object has positive buoyancy and will float. If the weight of the object is exactly equal to the weight of this displaced water, then the object has neutral buoyancy and thus be weightless. If the weight of the object is greater than the weight of this displaced water, then the object has negative buoyancy and will sink but it still weighs less than it did out of the water.Just remember buoyancy only affects the weight of the object, it has no effect on the mass of the object which remains constant in or out of water.
Buoyancy = weight of displaced fluid. 10 newtons = 9.8 kilograms with 1G of force applied in a vacuum.
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
ject weighs maximum in air ,hydrogen ,water, oil?
Weight is dependant upon gravity and the relationship to large bodies of mass such as planets. However, if you were to be put into a vacuum on the surface of the Earth, you would way less. There is air pressure pushing down on you and that would add some weight. It also pushes up on parts of you. The difference is not likely to be very significant, but it should be measurable. However, I don't volunteer to be the person in the vacuum chamber! I am not a scientist, but I believe that you would weigh very slightly more in a vacuum. Think of our atmosphere as being a liquid of very low density compared with water. An object that floats in water displaces water in the amount of the object's weight; if you put a scale under a floating object, the scale registers the object's weight as zero. A perfectly bouyant object has the same density (specific gravity) as water, and as such will have a substantial weight if measured on land. But it will have no weight if weighed in water. An object that sinks in water will have weight, but it will weigh its land weight minus the weight of water displaced by its volume. This should be the same for a person (in a pressure suit, of course). The person will not be bouyed up at all by the atmosphere.
Yes, when the object is submerged in water then water exerts opposite buoyonci force which decrease the weight of object.
The water around floating object's is a measure of that object's "Displacement". For the object to float the weight of displacement must equal the object's weight. If the water around an object is of a greater weight than an object's displacement, then the object will sink.
The difference between an object's weight, and the weight of water with the same volume as the object.
Archimedes principle states that : The force of buoyancy is equal to the weight of the displaced water. If the weight of the water displaced is less than the weight of the object , the object will sink. Otherwise the object will float , with the weight of the water displace equal to the weight of the object.
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
This phenomenon is called buoyancy and is caused by the object displacing water equal to its volume. If the weight of the object is less than the weight of this displaced water, then the object has positive buoyancy and will float. If the weight of the object is exactly equal to the weight of this displaced water, then the object has neutral buoyancy and thus be weightless. If the weight of the object is greater than the weight of this displaced water, then the object has negative buoyancy and will sink but it still weighs less than it did out of the water.Just remember buoyancy only affects the weight of the object, it has no effect on the mass of the object which remains constant in or out of water.
Buoyancy = weight of displaced fluid. 10 newtons = 9.8 kilograms with 1G of force applied in a vacuum.
The force of Buoyancy in water subtracts from the weight of the object in air.
An object will sink if it has a greater density than water. In this case, the weight of the water displaced by the object is less than the weight of the object.
When fully submerged on earth, yes. The net buoyancy force will be equal to the weight of the water displaced minus the weight of the object doing the displacing. Because the volume of water displaced by the water will be the same, and presumably have the same weight when the objects are both fully submerged, and the sphere of empty vacuum weighs less than the sphere of air, there will be a greater net upward buoyancy force on each object on earth.