The electron configuration of the 4f energy sublevel is the most stable is 4f to the 14th power. The electron configuration of outer sublevels that are most stable is 4d up to the 5.5s up to the 1st power.
The most stable electron configuration of the 4f energy sublevel is 4f7 or 4f14. In the 4f7 configuration, there would be only one electron in each of the seven orbitals and they would all have the same spin.
In the case of chromium (Cr), the electron configuration of 3d54s1 is more stable than 3d44s2. A half-filled sublevel is more stable than a sublevel that is less than half full. In the case of copper (Cu), the electron configuration of 3d104s1 is more stable than 3d94s2, again because a full sublevel and a half-filled sublevel is more stable.
Energy is required to disrupt a substrate's stable electron configuration
becasue when you remove a second elctron from Boron you are entering a new sublevel, the 2s sublevel, which already contains 2 electrons and is in a stable form, where as when you are removing a second electron from carbon it is still in the same energy sublevel, the 2p sublevel so it requires less energy
Neon has 8 valence electrons, which is a stable valence electron configuration.
Lithium is not completely stable.
Many stable ions have the configuration of a noble gas.
The noble gas configuration is known as the most stable configuration that an atom can achieve. In other words, the valence shell with ns2 np6 electron configuration.
There's two ways to answer this question. First electron configurations with half-filled sublevels are more stable then electron configurations that don't have half-filled sublevels. Since Selenium is one elctron away from achieving a more stable half-filled sublevel configuration it more readily gives up it's outermost electron, so less energy is requires to remove the outermost electron. Arsenic already has the stable configuration of half-filled sublevel so it wouldn't give up it's electron as readily, so more energy is required to remove it. Another way to look at it is that Selenium's outermost electron is in a p orbital that already has an electron so there is electron electron repulsion present in that orbital so it's attraction to the nucleus is less which is why less energy is required to remove it so the ionization energy is less. Arsenic has it's outermost electron unpaired in the p orbital so there is no electron electron repulsion present in that orbital so more energy is required to remove it then for Selenium's outer most electron. Hope this helps!
Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration. Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration.
Phosphorus must gain 3 electrons to achieve a stable electron configuration.
Na+ is the formula of the ion formed when sodium achieves a stable electron configuration.
The electron configuration of a neutral chromium atom is [Ar]3d54s1. The electron configuration for manganese is [Ar]3d54s2. The first electron removed from a chromium atom is the single 4s electron, leaving the electron configuration [Ar]3d5. The first electron removed from a magnesium atom is one of the 4s2 electrons, leaving the electron configuration [Ar]3d54s1. Removal of a second electron from a chromium atom involves the removal of one of the 3d electrons, leaving a configuration of [Ar]3d4, which is not a very stable configuration, and requires more energy to achieve. Removal of a second electron from a magnesium atom involves the removal of the second 4s electron, leaving a configuration of [Ar]3d5, which is more stable and requires less energy to achieve.
What symbol would represent a chlorine ion that has ionized to have a stable electron configuration?
The electron configuration of 10Ne is [1s2.2s2. 2p6]; it is very stable, obeying the 'Octet'-rule (like all noble gases do).
They achieve stable configuration by sharing their electrons in their outermost shell.
The electron configuration is responsible for this. If the elements have a stable electron configuration, they become inert.
Oxygen atoms need to share or gain two electrons in order to achieve a stable electron configuration.
Four: All of its valence electrons. If a silicon atom loses four electrons, it has the stable electron configuration of neon, while if the atom gains four electrons it has the stable electron configuration of argon. A silicon atom can also form a stable compound, as contrasted with a stable electron configuration for a single atom, by sharing four electrons with one or more other atoms.
electronic configuration is important for the matter to be stable or octet to be complete
The electron configuration of copper is: [Ar]4s13d10. It isn't 4s23d9 because Cu is able to obtain a more stable electron configuration when it takes an electron from the 4s and adds it to 3d. A half filled 4s and a completely filled 3d is more stable.
I honestly have no idea.
Beryllium is a metal. It has 2 valance electrons (in the outer shell), and therefore it tends to lose those electrons in order to achieve a stable electron configuration, which in the case of beryllium is also 2 electrons, but in the inner shell. Nitrogen is a nonmetal, with 5 valence electrons, and it tends to acquire more electrons in order to reach a stable electron configuration of 8. Less energy is need to lose electrons when the result is going to be a stable electron configuration.
When the highest occupied energy level of an atom is ﬁlled with electrons, the atom is stable and not likely to react.
Inert gases are the most stable ones, so if we try to add another electron, the stable electronic configuration is disturbed. So, we have supply energy for this process. Hence, electron gain enthalpy is positive.