The ideal gas equation.
PV = nRT
22o C = 295.15 Kelvin
(750 Torr)(X volume) = (1.5 moles O2)(62.36 L*torr/mol*K)(295.15 K)
Volume = 27608.331/750
= 37 Liters oxygen gas
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PV = nRT
The ideal gas equation.
50o C = 323.15 Kelvin
101.325 KPa = (1000 Pa/1 kPa)(1 atmosphere/101325 Pa)
= 1 atmosphere
-------------------------I needed to convert to be comfortable.
(1 atm)(X volume) = (3.2 mole O2)(0.08206 L*atm/mol*K)(323.15 K)
= 85 Liters in volume
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PV = nRT
Change Celsius to Kelvin and Torr can remain the same.
(750 Torr)(volume) = (1.5 mole)(62.36 Ltorr/molK)(295.15 K)
Volume O2 = 37 Liters
To determine the volume, use the ideal gas equation PV=nRT. Convert your pressure to atmospheres and compute. P is pressure, V is volume, n is moles, R is gas constant, and T is temperature.
Oxygen is just O and water is H2O
Type your answer here... we can make the solution of copper chloride for orsat apparatus.
Use a sample of pyrogallol (C6H6O6) in the sample followed by a combustion reaction. This compound absorbs oxygen present.
The chemical composition is determined on a dry and pure sample.
150 (50 x 3)
Iodine value= (B-S)N x 12.69 ------------------- wt of sample where, B=titration of blank S= titration of sample N= normality of thiosulphate
Oxygen is just O and water is H2O
The mean oxygen demand is the test done to indirectly determine the amount of organic compounds present in a water sample.
A sample size is needed whenever you conduct an experiment. How you determine an adequate sample size depends on the scope of what you're testing, such as medications.
I believe you want the equation to calculate the standard deviation of a sample. The equation is: s = square root[ sum from i =1 to n of (xi- xbar)/(n-1)] where xbar is the average of values of the sample and n = size of sample.
Factors that determine sample size
Take a simple random sample.
Melting point of the sample & Density of the sample
Type your answer here... we can make the solution of copper chloride for orsat apparatus.
If I understand the question correctly, the answer is the sample size.
A Sample to a Population
in every sample of carbon monoxide ,the mass ratio of carbon to oxygen is 3:4