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# Which is the best way to solve the equation x squared equals n?

###### Wiki User

If x squared equals n, then x is the square root of n.

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###### Wiki User

If x^2 = n, taking square roots of both sides, x = -sqrt(n) or +sqrt(n).

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## Related Questions

64x = 37 Divide both sides by 64: x = 37/64 or 0.578125

It is not possible, in general to solve one equation in two unknown variables. The best that you can do is rewrite the eqaution so that one variable is defined in terms of the other. xy = x - x2 = x(1 - x) Assuming x not 0 (else the original equation degerates to 0 = 0) we can divide both sides by x to give: y = 1 - x

You cannot go beyond x = k unless you know the value of k. And in that case, the equation is solved so there is nothing further to do!

X2 = k Take square root each side. X = (+/-) sqrt(k) ============

One linear equation is not sufficient to solve for two unknown variables (c and n). The best that you can do is c = 5(2n - 1)

6The line of best fit has the equation = -3 + 2.5x. What does this equation predict for a value of x = 3?Answer: 4.5

The best plan for that particular equation would be to first subtract 15 from each side, and then apply the quadratic formula.

boys+boys=silly is the same as 6721+6721=13442. the best hint to solve it is y=2 and s=1. you must then do math. sorry:(

This is a hyperbola. It is best approached using Fermat's factorisation method. Seefermat-s-factorization-methodor google wikepedia. I don't know of any faster approach.

Without an equality sign the given expression can't be considered to be an equation.

Using the quadratic formula to solve any quadratic equation is the best way of getting around it because the quadratic formula is "the opposite of b plus or minus the square root of b squared minus 4ac all divided by 2a. This formula only works with trinomials and second degree equaitons. If the equation is a binomial, then put in a placeholer (0) and substitute them into the equation.

That depends on the equation. In general, you'll try to isolate the variable, by using operations (on both sides of the equation) that get rid of anything other than the variable, on the side the variable is on.

You can't. It's an equation with two variables. It's a graph of a line. The best you can do with it is draw a graph, put a dot at (0,4) and another dot at (1,1) and draw a line through the dots.

You cannot solve a single linear equation with two variables. At best you can express one variable in terms of the other.

2x squared can best be describe as some variable being double and then squared.

I'm going to solve [ 2b = 10 ] for you, but I'm not going to do it in the best way.The best way is for you to make a date with your teacher to sit down and reviewsome of this stuff, so that you know how to do it.The way I'm going to do it, you'll have the solution to [ 2b = 10 ], but there will bethree problems with it:-- Nobody needs that information.-- You won't learn anything.-- If you need to solve [ 3d = 15 ] tomorrow, you'll be just as clueless as you are today.Here's the solution, and the method of finding it:1). Write down the equation :2b = 102). Divide each side of the equation by 2 :b = 5

That mass and energy are interchangeable substances. Energy = mass * speed of light squared Mass = energy/speed of light squared A direct mathematical relationship with the speed of light as a constant.

The best way to do this is use the general rule that you cross multiply and solve the resulting equation. The are other ways, but this one always works. Taking the top of the left by the bottom of the right, you get 4*54=216 Taking the bottom of the left by the top of the right, you get 9x 9x=216 x = 24&#9668;

This can be done at least 2 ways.Soln 1: The saying: IS over OF equals PERCENT over 100, tells how to set up a proportion to solve.5/28 = x/100 ... cross multiply and solve for x28x = 500x = 17.86%Soln 2: Translate the word problem into an equation. IS means equals, OF means to multiply.x (28) = 5 solve, get a decimal answer and convert it to a percent.x = 5/28 = 0.1786 = 17.86%Pick which method you like best to use.

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