To answer this question we need to first get the slope of the line 5x-4y=9 by rearranging it in the form of y=mx+b:
5x-4y=9
4y=5x-9
y=(5/4)x-9/4
Since the slope of parallel lines are negative reciprocals of each other, the negative reciprocal of 5/4 is -4/5, therefore the slope of a line parallel to the line 5x-4y=9 is -4/5
For two lines to be parallel they must have the same slope. A line parallel to a line with slope -2 would have a slope of -2.
5
Parallel lines have the same slope. So if you know the slope of a line in question, or you can calculate it, then you know the slope of any line parallel to that line.
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
if the slope of a line is 2/3, then the slope of a parallel line would be 2/3.
The line y = 6 is horizontal and has a slope of zero, as does any line that is parallel to it.
The slope is 5. Parallel lines always have the same slope.
-14
It will have the same slope which is 2
Slope = -1
The slope is -1 .
2.5
Any line with a slope of 1 is parallel to y=x-3.
The line 'Y = - 3' has a slope of zero. Any line parallel to it also has a slope of zero. The line parallel to it with a Y-intercept of 7 is: Y = 7
5
For two lines to be parallel they must have the same slope. A line parallel to a line with slope -2 would have a slope of -2.
5