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Why does silver iodide have a higher melting point than vanillin?

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Answered 2007-06-27 15:17:06

The attractive forces holding the molecules of silver iodide together (intermolecular forces) are stronger than those in vanillin, therefore they require more energy to break them. The attractive forces between two molecules of silver iodide are much stronger than the attractive forces between two molecules of vanilin. This is due to the different types of bonds found in each molecule - silver iodide molecules contain ionic bonds, which are very strong, while vanilin molecules contain covalent bonds which are a lot weaker. Since the attractive forces are higher in silver iodide, it requires a lot more energy (i.e. heat) to break these attractive forces in order to melt silver iodide, therefore it has a much higher melting point than vanilin. The bonding of atoms.

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Silver iodide is an ionic compound, whereas vanillin is a covalent compound. The bonds between atoms are much stronger in ionic compounds, so the melting point is higher in AgI.



= Potassium nitrate and Silver iodide


No. Silver iodide is insoluble in water.


Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3


Silver nitrate + potassium iodide -> silver iodide + potassium nitrate AgNO3 + KI -----> AgI + KNO3


Yellow precipitate (of silver iodide) shows the presence of iodide ions.


Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3


The molecular formula for silver iodide is AgI.Silver iodide is an inorganic, yellow compound which is used in many things, from silver-based photography to antiseptic.


Produces Silver iodide and Sodium nitrate


Potassium nitrate and a precipitate of Silver iodide are formed


At room temperature silver iodide is a yellow powdery solid.


Potassium nitrate and a precipitate of Silver iodide


produces Silver iodide and Sodium nitrate


Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3


Produces Silver iodide precipitate and Sodium nitrate


Ammonium iodide is NH4I Silver nitrate is AgNO3


silver nitrate and potassium iodide can be used.


If you add iodide (iodine ions) to Acidfied Silver Nitrate, a pale yellow precipitate is formed. This precipitate is Silver Iodide (AgI).


Dissolve each of the silver nitrate and potassium iodide separately in water, then mix the two solutions slowly with stirring. Silver iodide will precipitate and can be separated by filtering it from the liquid.


Yes, Iodide is a monatomic anion. There are several types of Iodides such as potassium iodide, hydrogen iodide, and silver iodide.



A replacement reaction yielding silver iodide and potassium nitrate.


No.While vanillin is an aldehyde, which should react with Tollens' reagent to precipitate silver metal, vanillin does not "pass" Tollens' test. Tollens' reagent is very basic (sodium or potassium hydroxide). Vanillin has a phenolic hydrogen (OH bonded to a phenyl ring) which is slightly acidic. Vanillin will react first with the excess hydroxide ions in solution to form a phenoxide salt, which will not participate in the silver-precipitating reaction.


Silver and iodine, when combined, forms Silver Iodide (AgI). Silver iodide is not soluble in water and will form a precipitate.



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