To prevent the magnesium or sodium reacting with oxygen in the air
The straight simple answer is sodium metal and also magnesium. Titanium ore is usually reacted with chlorine to produce TiCl4 often known as "tickle four". This is very volatile which makes it easy to purify by distillation. The purified tickle four is now reacted with sodium metal to produce sodium chloride and titanium sponge. TiCl4 + 4Na ------> 4NaCl + Ti However, other reactive metals are often used such as magnesium which in many ways is far easier to handle than sodium.
The limiting reagent is sodium hydroxide.
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
They wont react with ammonium chloride, they react to form it.
calcium chloride
Magnesium chloride: 81,95 g are obtained.
The straight simple answer is sodium metal and also magnesium. Titanium ore is usually reacted with chlorine to produce TiCl4 often known as "tickle four". This is very volatile which makes it easy to purify by distillation. The purified tickle four is now reacted with sodium metal to produce sodium chloride and titanium sponge. TiCl4 + 4Na ------> 4NaCl + Ti However, other reactive metals are often used such as magnesium which in many ways is far easier to handle than sodium.
Let's see.Mg + 2HCl -> MgCl2 + H2Looks like magnesium chloride. And a little hydrogen gas.
Mg(OH)2 + 2HCl >> MgCl2 + 2H2O
Magnesium generally appears in two valence forms. The pure, non-reacted element, Magnesium, has no charge. Reacted Magnesium has a valence of +2
The limiting reagent is sodium hydroxide.
This is when acetylene reacted with one of the magnesium bromide. For instance, acteylene reacted with methyl magnesium bromide forming 3-hexa-1-eyne.
magnesium
magnesium + chlorine --> magnesium chloride Mg (s) + Cl2 (g) --> MgCl2 (s) 5.60 g Mg x 1 mol Mg x 1 mol MgCl2 x 95.21 g MgCl2 = 21.9 g MgCl2 ..................24.31 g Mg. 1 mol Mg........ 1 mol MgCl2
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
nothing
They wont react with ammonium chloride, they react to form it.