Math and Arithmetic
Physics
Kinematics

# Why is average speed distance divided by time but average velocity is initial velocity plus final velocity divided by 2?

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Because velocity is a measurement of change of speed rather than an average constant speed. To get the average speed (as you rightly said) - you divide the total distance travelled by the time taken. The average velocity is the change in speed over time (either an increase or decrease).

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## Related Questions   The average acceleration from zero is the final velocity divided by the amount of time to reach that velocity. Average speed = 1/2 (initial speed + final speed) Time = (distance)/(average speed) Velocity = distance divided by time / Velocity = average speed over time / Acceleration = (change of) velocity divided by time elapsed Change in velocity = final velocity "minus" initial velocity divided by time elapsed  The formula for average velocity is: Final velocity + Initial velocity.... then divide by 2 [ (Vf + Vi) / 2 ]. Your answer should be in your measurement of length divided by seconds [ex. m/s] Distance = |(v2 - u2)/(2a)| where initial velocity = u final velocity = v accelaration = s Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity. You can't. All you can tell from time and distance is the average speed during that time. There are several definitions. not just one. Average velocity in a direction = Average displacement (distance) in that direction/time Instantaneous velocity in a direction = derivative of displacement in that direction with respect to time Average velocity in a direction = Initial velocity in that direction + Average acceleration in that direction * time Instantaneous velocity in a direction = Definite integral of acceleration in that direction with respect to time, with initial velocity at t = 0 Then there are others in which time is eliminated. If acceleration is 0 then s = u*t s = distance u = initial velocity t = time final velocity - initial velocity divided by time average velocity is the displacement over time while instantaneous velocity refers to the velocity of an object at one point or at as pecific point of time. *displacement is the difference between the initial position and the final position of an object. (distance 2 - distance 1)  Final Velocity minus Initial Velocity (all together this is the change in velocity) divided by the average acceleration will give you the time it took for the object to reach that speed.(Vf - Vi) / Aaverage = Time Velocity is equal to distance traveled divided by the time it took to travel. v = d / t Velocity also equals the initial velocity plus the acceleration times time. v = v1 + a(t) Is a change in velocity (increase/decrease). It also equals; final velocity-initial velocity divided by time Acceleration = final velocity - initial velocity divided by time Acceleration is an object's change in velocity divided by its change in time. So: acceleration=(final velocity - initial velocity)/(final time - initial time) To calculate Average velocity: ( Vf - Vi ) / t Where Vf is Final Velocity Vi is Initial Velocity t is Time Average Acceleration can be verbally defined as the change in velocity in a certain change in time... More simply put: Average Acceleration = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) Velocity = distance final - distance initial/ time final - time initial V = -4.1 cm - 3 cm/5.0 s - 3.0 s = -7.1/2 velocity = -3.6 m/s v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.

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