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Imide is acidic as its H+ can be released. The two strongly electronegative carbonyl O are capable of withdrawing the unshared pair of electrons on N as well as the electrons making the N-H bond. This weakens the N-H bond. After the H+ is released, the anion is stabilised by resonance.

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In dilantin sodium why is the imide proton abstracted rather than the amide proton?

If a proton on N between two C=O's is removed by a base, one can draw two resonance structures, one involving each C=O, to stabilize the resulting anion. However, with an amide, there is only one C=O and when the H is removed, only one resonance structure can be drawn. As a result, the amide H is less acidic than the imide H.


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Imides are more acidic than amides because the hydrogen atom in imides is present on a nitrogen atom that is more electronegative than the oxygen atom in amides. This greater electronegativity leads to a more stable conjugate base after deprotonation, making the imide more acidic.


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