Simple Answer:
The shape of the magnetic field of a uniformly wound solenoid is very nearly identical to the field produced by a uniformly magnetized permanent magnet with the same physical shape as the solenoid.
For the Experts:
This is a consequence of the mathematical equivalence of the source of the magnetic field as created by a current and the source of a magnetic field as created by the curl of the magnetization density of permanent magnet.
Inside the hollow cylindrical electromagnet ("solenoid"), the magnetic field lines are straight, parallel to each other, and parallel to the axis of the cylinder. They get more complicated at the ends, but the above statement is good for a solenoid of infinite length, which has no ends, and is a good approximation in the center of a real one.
A solenoid is a long cylindrical coil of wire consisting of a large number of turns bound together very tightly. A solenoid is usually used to produce a magnetic field to pull the armature of a relay, causing electrical contacts in the relay to open and/or close switching current flow.
The magnetic field outside a solenoid is not zero. This is only true for an infinitely (thus unreal) long solenoid. Infinitely long solenoids cannot be found in nature, but are often used as a good approximation of reality because they are much simpler to work with mathematically. The magnetic field outside a real solenoid is less dense than outside the solenoid and often one is only concerned with the field inside, which is approximately constant (deviations occur near the edges), so using an infinitely long solenoid is a good model.
B is non-zero outside a solenoid because magnetic field lines make closed loops so when they pass through the solenoid they also emerge from it thats why.
A current circulating in a hollow copper coil (solenoid) produces a magnetic field equal to the permeability times the turns density times the current. B = μ x n x I * B is the magnetic field measured in Tesla * μ is the relative permeability of the solenoid's core which is air in this example and have a value approximated to 1.25663706E-6 * n is the turns density which equals the number of turns divided by the solenoid length n = N/L where L is measured in meters. * I is the current flowing within the solenoid and measured in Amperes
The magnetic field produced by electric current in a solenoid coil is similar to that of a bar magnet.
Inside the hollow cylindrical electromagnet ("solenoid"), the magnetic field lines are straight, parallel to each other, and parallel to the axis of the cylinder. They get more complicated at the ends, but the above statement is good for a solenoid of infinite length, which has no ends, and is a good approximation in the center of a real one.
Solenoid is a helically wound coil of wire. If current flows through the wire then an intense magnetic field is produced along the axis of the solenoid. This magnetic field would induce magnetism in the ferro magnetic piece placed along the axis of the solenoid.
yes - need to run electricity through it to make it a linear magnetic generator.
When current is passed through a solenoid coil, magnetic field produced due to each turn of solenoid coil is in the same direction. As a result the resultant magnetic field is very strong and uniform. The field lines inside the solenoid are in the form of parallel straight lines along the axis of solenoid. Thus, the solenoid behaves like a bar magnet.
A solenoid acts like a magnet when an electrical current is sent through the coil. A permanent magnet is magnetic all the time. Therefore, they are similar when both act like a magnet, but not when the solenoid is turned off.
A solenoid is a long cylindrical coil of wire consisting of a large number of turns bound together very tightly. A solenoid is usually used to produce a magnetic field to pull the armature of a relay, causing electrical contacts in the relay to open and/or close switching current flow.
The strength of the magnetic field produced by a current carrying solenoid depends on:The number of turns - larger the number of turns, greater is the magnetism produced.The strength of the current - when current increases, magnetism also increases.Nature of 'core-material' used in making the solenoid - if we use soft-iron as a core for the solenoid, then it produces the strongest magnetism.
A solenoid is a long cylindrical coil of wire consisting of a large number of turns bound together very tightly. A solenoid is usually used to produce a magnetic field to pull the armature of a relay, causing electrical contacts in the relay to open and/or close switching current flow.
Yes, The numerical amount of voltage and current produced (or consumed) by the solenoid is related to the "change in magnetic flux per unit time" For example, consider a permanent magnet with a 0.2 T surface flux density and a coil with 100 turns and an ideal inductor core. Now the permanent magnet is moved from an infinite distance to touching the surface of the coil in a time dT= .1 seconds. The max voltage produced across the coil will be equal to N*dI / dT, in this case 100*.2 / .1 = 200 V. Incidentally that is the peak voltage of a 120 volt RMS wave. This effect relates to the dipole moment and magnetic inertia of a material. For example current carrying copper wire near an iron core will induce a large magnetic flux, in which a percentage of this material's free crystal regions align. Moving a permanent magnet near this core will also produce a changing alignment of the cores crystal lattice, equivalent to a straight wire moving through a perpendicular magnetic field at a velocity. A rectifier may be useful on the output of the solenoid to produce dc.
Factors affecting the magnetic field strength of a solenoid are: - length of the solenoid - diameter of the solenoid - current through the coil around the solenoid - number of turns of the coil of current around the solenoid, usually turns of wire - material in the core
A relay is a switch - a solenoid produces a magnetic field.