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Some of the subscripts are used incorrectly

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11y ago

Some of the subscripts are incorrectly used.

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Q: Why is the equation incorrect Mg3 N2 Mg3N2?
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Related questions

What is the balanced equation between magnesium nitrogen and magnesium nitride?

3Mn + N2 ----> Mn3N2 its actually 3mg+N2(arrow) Mg3N2


What is balance equation for magnesium plus nitrogen?

Mg+ 2HNO3-->Mg(NO3)2 + H2 Products are Magnesium nitrate and Hydrogen gas.


Is the coefficient sequence needed to balance the chemical equation Mg N2 yield Mg3N2?

3 Mg + N2 = Mg3N2


What are the coefficient in 3Mg N2 - Mg3N2?

a coefficient is the number that falls before the chemical formula.so,in 3Mg N2 - Mg3N2 there are 3 coefficients in that chemical equation. These are present on the reactants side.


How do you solve mgcl2 plus n2?

3 MgCl2 + N2 = Mg3N2 + 3 Cl2


Why does Mg3N2 form in insufficient air?

Magnesium nitride (Mg3N2) is formed by the reaction of magnesium metal (Mg) with nitrogen gas (N2).


What is Mg2NO3?

There is no compound with the formula Mg3NO2. There is one with the formula Mg3N2, which is magnesium nitride. Magnesium nitride is an inorganic yellow-green powder.


What is chemical equation for magnesium nitride?

The chemical formula for magnesium nitride is Mg3N2. There are two reactions in which Mg3N2 can be prepared which are represented by the following equations:3Mg+N2+heat (800 C)---> Mg3N23Mg+2NH3+heat (700 C)---> Mg3N2 + 3H2Source: https://en.wikipedia.org/wiki/Magnesium_nitride


How many grams of magnesium nitride can be made from 55.3 grams of magnesium if all the magnesium reacts only with nitrogen?

Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================


What reaction is magnesium with N?

Magnesium + Nitrogen ----> Magnesium Nitride3 Mg + N2 ----> Mg3N2


3 atoms of magnesium combine with 2 atoms of nitrogen.What will be the weight of magnesium which combines with 1.86g of nitrogen?

Equation: 3Mg + N2 → Mg3N2 3mol Mg combines with 1mol N2. Molar mass N2 = 28.014g/mol 1.86g N2 = 1.86/28.014 = 0.0664mol N2 This will require 0.0664*3 = 0.1992mol Mg Molar mass Mg = 24.305g/mol 0.1992mol Mg = 24.305*0.1992 = 4.84g Mg required.


How many moles of Mg3N2 would be produced when 180.0 g of Mg reacts with 85.0 g of N2?

3.03