The alkali metals are Li,Na,K,Rb,Cs,Fr.If v see their general electronic configuration,v see that its (n-1)p6 ns1.That means the outer most s orbital contains 1 unpaired electron and just in the inner shell there is fully filled p orbital. 1st ionisation energy is the amount of energy required to remove 1st electron from the outermost shell of an isolated gaseous ion.here v see that the energy required 2 remove 1 electron from outermost shell will be very less cos it helps the atom to achieve fully filled stable electronic configuration. On the other hand,2nd ionisation energy is the energy required 2 remove an electron from isolated gaseous +1 atom,means atom from where 1 electron has already been removed. So here,it is very difficult to remove 1 more electron from the stable fully filled p orbital and large amount of energy is needed.Hence the 2nd IE shoots up considerably as compared to d 1st IE. Hope it's clear...:)..
Think about what happens when you ionize an alkali metal (keeping in mind that alkali metals are the first group and contain 1 valence electron). When you ionize an alkali metal, you remove it's one valence electron. The first ionization energy is relatively low, because this actually stabilizes the atom. However, the second ionization energy is much higher because the already ionized alkali metal now contains a stable outer shell and is much less willing to lose another electron.
The alkali metals are Li,Na,K,Rb,Cs,Fr.If v see their general electronic configuration,v see that its (n-1)p6 ns1.That means the outer most s orbital contains 1 unpaired electron and just in the inner shell there is fully filled p orbital. 1st ionisation energy is the amount of energy required to remove 1st electron from the outermost shell of an isolated gaseous ion.here v see that the energy required 2 remove 1 electron from outermost shell will be very less cos it helps the atom to achieve fully filled stable electronic configuration. On the other hand,2nd ionisation energy is the energy required 2 remove an electron from isolated gaseous +1 atom,means atom from where 1 electron has already been removed. So here,it is very difficult to remove 1 more electron from the stable fully filled p orbital and large amount of energy is needed.Hence the 2nd IE shoots up considerably as compared to d 1st IE. Hope it's clear...:)..
The attraction between the electrons involved and the atomic nucleus is stronger.
There is no relation ship. They have the lowest ionization energies.
As you go down the group (any group), ionization energy decreases. So in terms of ionization energy, for the alkali metals, Lithium > Sodium > Potassium > Rubidium > Caesium > Francium
It is about first ionization energy. It is less than alkaline earth metals.
Chlorine has a higher ionization energy. Chlorine's tendency is to gain electrons, not lose them as metals usually do.
the lowest ionization energy in IA :hydrogen ,lithiun ,sodium and potassium
There is no relation ship. They have the lowest ionization energies.
As you go down the group (any group), ionization energy decreases. So in terms of ionization energy, for the alkali metals, Lithium > Sodium > Potassium > Rubidium > Caesium > Francium
It is about first ionization energy. It is less than alkaline earth metals.
Chlorine has a higher ionization energy. Chlorine's tendency is to gain electrons, not lose them as metals usually do.
the lowest ionization energy in IA :hydrogen ,lithiun ,sodium and potassium
Alkali gases only have 1 electron needing to be removed to reach a stable noble gas configuration. Alkaline earths have two electrons. Alkali metals thus have the lower ionization energy of the two groups.
The first level ionization energy oif aluminium is 577,5 kJ/mol.All alkali metals have lower values for the ionization energy.
Group IIA metals (alkali earth) become more reactive with non-metals as you go higher in atomic numbers.
Alkali metals (group 1 elements) have one valence electron. Hence have one ionization energy Alkaline earth metals (group 2 elements) have two valence electron. Hence have two ionization energy
Francium (Fr) has the lowest Ionization potential.
yes, they are, as they have the least ionization energy among all elements
Alkali gases only have 1 electron needing to be removed to reach a stable noble gas configuration. Alkaline earths have two electrons. Alkali metals thus have the lower ionization energy of the two groups.