This is because in acidic medium kmn04 decomposes to give Mn2+ ions which impart pink colour to the solution.
The reaction being
Mno4- +8H+5e ----->Mn2+ + 4H2O
The permanganate ion, MnO4- purple in colour. The sulfuric acid is added to create acidic conditions. In acidic conditions, the MnO4- gets reduced to Mn2+ which is colourless. Therefore, judging by the colour change, we can figure out how much of the potassium permanganate has been used.
alkaline
use an acidic solution .... something as simple as lemon or lime juice will work
coz the oxidation state of manganese ion changes from +7 to +4. as a result Mno2 is formed which is brown in colour hence titration colour change cannot be detected
toluene is benzene with CH3 reacting this with KMnO4 in acidic solution will produce a benzene with a carboxylic acid (CH3 will be oxidized)
The permanganate ion, MnO4- purple in colour. The sulfuric acid is added to create acidic conditions. In acidic conditions, the MnO4- gets reduced to Mn2+ which is colourless. Therefore, judging by the colour change, we can figure out how much of the potassium permanganate has been used.
alkaline
Permanganate(purple) becomes Mn2+(pale pink) and Iodide becomes Iodine.
Acidic conditions promote the oxidation of toluene by potassium permanganate.
permanganate ion is an oxidising agent and is reduced.
use an acidic solution .... something as simple as lemon or lime juice will work
coz the oxidation state of manganese ion changes from +7 to +4. as a result Mno2 is formed which is brown in colour hence titration colour change cannot be detected
Well the question is not very specific, but I think you may be reffering to the boiling of water before acid-base titrations. Water is boiled previous to acid-base titrations because if left open to the atmosphere @ STP water will absorb carbon dioxide until the pH is roughly 5.5. This will obviously adversly affect the accuracy of an acid-base titration. In the permanganate titration, a redox reaction occurs in the presence of an acidic solution.
Unless the solution is made acidic or basic, the two will dissolve and form a solution of potassium ions, permanganate ions and iodide ions.
Potassium manganate = K2MnO4 Potassium permanganate = KMnO4 It is important to quote the oxidation state of the compound. Potassium manganate could easily be potassium manganate (VI) as opposed to potassium manganate (VII) KMnO4 Potassium manganate (VI) K2MnO4 is a dark green compound made by fusing manganese (IV) oxide with potassium hydroxide. It is stable in basic solution In aqueous acidic solution it disproportionates to the manganate (VII) ion and manganese (IV) oxide.
toluene is benzene with CH3 reacting this with KMnO4 in acidic solution will produce a benzene with a carboxylic acid (CH3 will be oxidized)