Program for row wise sort for a square matrix in C?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int a[10][10],i,j,k,m,n;

printf("enter the order");

scanf("%d",&m,&n);

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

{

scanf("%d",&a[i][j]);

}

}

for(k=0;k<m;k++)

{

for(i=0;i<=m-1;i++)

{

for(j=0;j<n-i-1;j++)

{

if(a[k][j]>a[k][j+1])

temp=a[k][j];

a[k][j]=a[k][j+1];

a[k][j+1]=temp;

}

}

}

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

{

printf("sorted matrix=%d",a[i][j]);

}

}

getch();

}

Answer 2

int i, j;

printf("\nEnter number of rows & cols of array A: ");

scanf("d", &m, &n);

printf("\nEnter elements of array A:\n");

for(i=0; i<m; i++)

for(j=0; j<n; j++)

scanf("%d", &a[i][j]);

printf("\nEnter number of rows & cols of array B: ");

scanf("d", &x, &y);

printf("\nEnter elements of array B:\n");

for(i=0; i<x; i++)

for(j=0; j<y; j++)

scanf("%d", &b[i][j]);

printf("\n\nArray A:\n\n");

for(i=0; i<m; i++)

{

for(j=0; j<n; j++)

printf("\t%d", a[i][j]);

printf("\n\n");

}

printf("\n\nArray B:\n\n");

for(i=0; i<x; i++)

{

for(j=0; j<y; j++)

printf("\t%d", b[i][j]);

printf("\n\n");

}

multiply();

printf("\n\nArray after multiplication:\n\n");

for(i=0; i<m; i++)

{

for(j=0; j<y; j++)

printf("\t%d", c[i][j]);

printf("\n\n");

}

getch();

}

void multiply()

{

int i, j, k;

if(m != y n != x)

{

printf("\n\nMultiplication is not possible.");

exit();

}

else

for(i=0; i<n; i++)

for(j=0; j<x; j++)

{

c[i][j] = 0;

for(k=0; k<y; k++)

c[i][j] = c[i][j] + a[i][k] * b[k][j];

}

}