Write a program in c language to draw a diamond shaped if you give the number?

Answer 1

Hey, It is not the exact logic for a given program.

Here i m giving the code with minimum number of executing steps.

also i m sure that there doesn't exist any other way to print the same Diamond such that code executing steps will be less than mine.

It is not copied from any website, book etc.

#include

void main()

{

int n,i,s,k,flagReverce=0;

printf("Enter the no. of rows\n");

scanf("%d", &n);

for (i=1; i>=1; i++)

{

for (s=n; s>i; s-)

printf(" ");

for(k=1; k<(i*2)-1; k++)

printf("*")

printf("\n")

if (i == n)

flagReverce = 1

if (flagReverce = 1)

i-=2

}

}

Answer 2

#include<stdio.h>

main()

{

int i,j,k,n,a,b,c,x;

printf("enter the # of rows of graphical output");

scanf("%d",&n);

/* UPPER HALF OF KITE */

for(i=1;i<=n;i++)

{

printf("\t");

for (k=1;k<=(n-i);k++)

{

printf(" ");

}

for(j=0;j<i;j++)

{

printf("*");

printf(" ");

}

for(k=1;k<=(n-i-1);k++)

{

printf(" ");

}

printf("\n");

}

/* LOWER PART OF KITE */

for(i=(n-1);i>0;i--)

{

printf("\t");

for (k=(n-i);k>0;k--)

{

printf(" ");

}

for(j=i;j>0;j--)

{

printf("*");

printf(" ");

}

for(k=(n-i-1);k>0;k--)

{

printf(" ");

}

printf("\n");

}

getch();

}