The line 'Y = - 3' has a slope of zero. Any line parallel to it also has a slope of zero. The line parallel to it with a Y-intercept of 7 is: Y = 7
Since the two lines are parallel, then they have the same slope, 3. Thus, the equation of the line with y-intercept -4, and parallel to y = 3x - 3 is y = 3x - 4.
parallel to y=4x-3 so they have the same gradient of 4 y intercept is positive 1 so y=4x+1
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
find equation of the line. write equation in slope intercept form. (5,5) parallel line (3,13) and (12,13)
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
Start with the equation y = 2 Put that into slope-intercept form: y = 0x + 2 Change the y-intercept to 3 y = 0x + 3 or simply y = 3. This is a bit of a trick question to see if you understand the terminology. The line y = 2 is parallel to the x-axis, two spaces above it. A line parallel to that would also be parallel to the x-axis, and the intercept of 3 means that it is 3 spaces above the x-axis at the center of the graph. It remains 3 units above the x-axis out to infinity.
By including the + or - signs in the question
It is a straight line equation and can be rearranged into slope intercept form as follows:- 6x-6y = 12 -6y = -6x+12 y = x-2 which is now in slope intercept form
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
The given equation is : x + 5 + y = 0 Write in standard form of equation of straight line : y = mx + c . Where m is slope and c is y-intercept. We get: y = -x - 5 Which gives slope = -1 y-intercept = -5 To get x-intercept put y = 0 in the equation. We get x-intercept = -5
y= slope + y-intercept
1. Write the equation in y=mx+b. 2. b is the y-intercept. Ex. 1. y=9x+0 2. b=0. The y-intercept of y=9x is 0. Hint: Since this is a direct variation problem (y=kx), the x-intercept is also 0.
Given point: (6, 7) Equation: 3x+y = 8 Parallel equation: 3x+y = 25
plug in the slope(m) and coordinates (x,y) into the slope-intercept formula & solve for b.slope-intercept formula: y=mx+b
Slope-intercept form means to solve for y. So let's rearrange our equation from 2x - y = 12 to y = 2x - 12. Now the equation is in slope intercept form (y = mx + b, where m is slope and b is the y-intercept). Therefore, 2 is the slope and -12 is the y-intercept.
You have to solve the equation for "y", in other words, change it to a form where "y" is on the left, and everything else to the right. You will get an equation of type y = ax + b, where a is the slope, and b the y-intercept.
Write the equation of the line below in slope-intercept form (y=mx+b): 📷
y = mx + b, where m is the slope and b is the y-intercept.
It is not an equation because it doesn't have an equal sign in it so to write it in slope-intercept form is impossible
As for example if the slope is 3 and the y intercept is 6 then the equation is: y=3x+6
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).