0
What else can I help you with?
How many grams do you need to add to prepare a 2M solution if you have 2L solution?
4 gram molecular weights (moles): However many grams four moles* of the solute is. * Hint: four moles of sodium chloride weighs less than four moles of sucrose.
How many moles are contained in 0.455L of a 7.182 M solution?
This is a chemical calculation. there are 3.267 moles in this solution.
How many milliliters of concentrated 8 M solution is needed to make 900 ml of 2 M solution?
237.5 mL (200mL if you are keeping track of significant figures). Molarity is moles/liters. To make 900mL of a 2M solution, you need 1.8 moles of solute. There are 1.8 moles of solute in 237.5 mL of 8M solution.
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
How many grams of solid KOH is necessary to prepare 60ml of 2M KOH solution?
Moles KOH = Molarity x Volume = 0.214 moles/liter x 0.0602 liters = 0.0129 moles KOH. Remember, 60.2 mL = 0.062L
How many moles of hno3 are needed to prepare 5.0 of a 2.0 m solution of hno3?
10
How many moles of agno3 are needed to prepare 0.50 l of a 4.0 m solution?
Molarity = moles of solute/liters of solution or, for our purposes moles of solute = liters of solution * Molarity moles of AgNO3 = 0,50 liters * 4.0 M = 2.0 moles of AgNO3 needed --------------------------------------
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?
4 moles or 160 g NaOH is required for one litre solution.
How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
How many moles of Fe3O4 are needed to prepare 4.74 moles of Fe2O3?
7.18
How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
How many moles of potassium hydroxide are required to prepare 300 mL of 0.250 M solution?
To calculate the moles of potassium hydroxide needed, use the formula: moles = molarity * volume (in liters). First, convert 300 mL to liters (0.3 L). Then, moles = 0.250 mol/L * 0.3 L = 0.075 moles of potassium hydroxide needed to prepare the solution.
How many grams of koh are needed to prepare 250 milliliters of a 2 m solution of koh formula mass 56?
To prepare a 2 M solution of KOH, you would need to calculate the moles of KOH required first. Then use the formula mass of KOH (56 g/mol) to convert moles to grams. First, calculate the moles needed: 2 moles/L * 0.25 L = 0.5 moles. Then, convert moles to grams: 0.5 moles * 56 g/mole = 28 grams of KOH needed.
How many moles of copper sulfate are needed to make 2.50 Liters of 0.125 moles solution?
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
How many moles of NaI would you need to prepare 2L of a 2M NaI solution?
599.6
How many liters are needed to make a 0.25 M solution with 0.50 moles moles of C12H22O11?
To find the volume of solution needed, you can use the formula: moles = Molarity × Volume. Rearranging the formula to solve for volume: Volume = Moles / Molarity. Plugging in the values, you get Volume = 0.50 moles / 0.25 M = 2 liters of solution needed.
