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Is it true that 1M KOH equals 1M C7O2H7?
No, 1M KOH (potassium hydroxide) does not equal 1M C7O2H7 (pimelic acid). They have different chemical formulas and properties, so their molarities cannot be equated in general chemical reactions or calculations.
How do you prepare 30 percent of methanolic KOH solution?
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
What volume of a 3m koh solution can be prepared by diluting 0.5 l of a 5m koh solution?
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
Is it true that 1M KOH equals 1M C7O2H7?
No, 1M KOH (potassium hydroxide) does not equal 1M C7O2H7 (pimelic acid). They have different chemical formulas and properties, so their molarities cannot be equated in general chemical reactions or calculations.
How can we prepare 1M solution of NaCl?
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Why alcohol is required in koh solution?
because KOH is hygroscopic
If you have 2 liters of 2 M NaCl you take 500 ml of that and add it to 500ml of pure water the new 1000 ml preparation is now?
A solution of NaCl 1 M.
What is the role of KOH in the preparation of potassium manganate?
KOH is the reactant in this reaction:2 MnO2 + 4 KOH + O2 = 2 K2MnO4 + 2 H2O
What is the molarity of a solution when 50.0ml of a 4.00M KOH solution is diluted to 200ml. what is the percent concentration of KOH in this final solution. asume the density of 1.0gmole?
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
How many grams of KOH are present in 31.5 mL of a 7.26M KOH solution?
The answer is 12,831 g KOH.
How do you prepare 30 percent of methanolic KOH solution?
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
How do you make 5 percent potassium hydroxide solution?
A solution that is refered to as a percentage of something (like potassium hydroxide, KOH) refers to the mass of the solute compared to the total solution, so a 5% KOH solution would be 5g KOH + 95g H2O, and the 5g KOH would be 5% of the 100g total of the solution.
What volume of a 3m koh solution can be prepared by diluting 0.5 l of a 5m koh solution?
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
