The compound is AlCl3, three electrons are transferred. Al has an oxidation number of +3, Cl -1
In a combination reaction between sodium (Na) and chlorine, electrons are transferred from sodium to chlorine. This results in the formation of sodium ions (Na+) and chloride ions (Cl-), which then combine to form sodium chloride (NaCl) through ionic bonding.
The ionic compound formed between aluminum and chlorine is aluminum chloride (AlCl3). In this compound, aluminum donates three electrons to each chlorine atom to form a stable ionic bond.
Three electrons are transferred to form a bond between aluminum and sulfur because aluminum has 3 valence electrons while sulfur has 6 valence electrons. Aluminum donates its 3 electrons to sulfur, completing the octet for both atoms and forming an ionic bond.
Aluminum foil has metallic bonds, where aluminum atoms share their electrons with surrounding atoms to form a uniform structure. This differs from ionic bonds where electrons are transferred between atoms or covalent bonds where electrons are shared between atoms.
In the ionic bond between sodium and chlorine in NaCl, one electron is transferred from the sodium atom to the chlorine atom. Sodium becomes positively charged and chlorine becomes negatively charged, forming the ionic bond.
Only one, from sodium to chlorine.
Only one electron is transferred.
In a combination reaction between sodium (Na) and chlorine, electrons are transferred from sodium to chlorine. This results in the formation of sodium ions (Na+) and chloride ions (Cl-), which then combine to form sodium chloride (NaCl) through ionic bonding.
The ionic compound formed between aluminum and chlorine is aluminum chloride (AlCl3). In this compound, aluminum donates three electrons to each chlorine atom to form a stable ionic bond.
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One electron is transferred from each sodium to each chloride.
Three electrons are transferred to form a bond between aluminum and sulfur because aluminum has 3 valence electrons while sulfur has 6 valence electrons. Aluminum donates its 3 electrons to sulfur, completing the octet for both atoms and forming an ionic bond.
Aluminum foil has metallic bonds, where aluminum atoms share their electrons with surrounding atoms to form a uniform structure. This differs from ionic bonds where electrons are transferred between atoms or covalent bonds where electrons are shared between atoms.
In the ionic bond between sodium and chlorine in NaCl, one electron is transferred from the sodium atom to the chlorine atom. Sodium becomes positively charged and chlorine becomes negatively charged, forming the ionic bond.
The single valence electron of a neutral sodium atom is transferred to the valence shell of a neutral chlorine atom to form the stated bond; therefore, the answer is 1.
The chemical formula of the ionic compound formed between aluminum and chlorine is AlCl3. Aluminum gives away 3 electrons to form a 3+ cation, while chlorine gains one electron to form a 1- anion. The resulting compound has a one-to-one ratio of aluminum to chlorine ions.