2,55 moles of the compound CO have 71,4 grams.
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
30.0 grams carbon (1 mole C/12.01 grams) = 2.50 moles carbon ===============
Two molecules of Carbon monoxide. I think not two molecules but two moles of carbon monoxide .i,e 2CO.
The mass of 4,5 moles of carbon is 54,04815 g.
The number of grams in 20 moles of carbon is 240,22 g.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
1.305 mol CO
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
To find the mass of carbon monoxide needed, we need to use the stoichiometric ratio between iron and carbon monoxide. From the balanced equation, we can see that 3 moles of carbon monoxide produce 2 moles of iron. First, calculate the molar mass of iron (Fe), which is 55.85 g/mol. Next, use the molar ratio between iron and carbon monoxide (2:3) to find the moles of carbon monoxide required. Finally, convert the moles of carbon monoxide to grams using its molar mass (28.01 g/mol).
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.5 grams / 28.0 grams = .161 moles CO
30.0 grams carbon (1 mole C/12.01 grams) = 2.50 moles carbon ===============
Two molecules of Carbon monoxide. I think not two molecules but two moles of carbon monoxide .i,e 2CO.
1,4 moles carbon monoxide are produced.
The mass of 4,5 moles of carbon is 54,04815 g.
The number of grams in 20 moles of carbon is 240,22 g.